Extracting and storing part of output with shell script

Question

The find command gives me output like

a/b/1.xml
a/1.xml
c/d/fd/fg/2.xml

I need to write a Bash command to be able to store only data after last / in a path.

doing find . -name "*.xml" >>mayflies.txt gives me the full path and stores it, but I need just the .xml part to store.

How can I do that? I was trying options like cut, but then, due to variable pattern, I got lost on how to make it work.

Arton Dorneles · Accepted Answer · 2016-03-03 23:25:57Z

1

You can combine cut with rev to obtain what you want:

find . -name "*.xml" | rev | cut -d'/' -f1 | rev >> mayflies.txt

answered Mar 3, 2016 at 23:25

Arton Dorneles

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Comments

fukanchik · Accepted Answer · 2016-03-03 23:25:47Z

0

Try this:

find . -name '*.xml' -exec basename '{}' \;

instead of just printing the result, it executes unix command basename to print only file name of what was found.

answered Mar 3, 2016 at 23:25

fukanchik

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