Workout if a string holding a version number is higher than another string holding a version number in Python 3.
This is what I have tried:
request_version = "1.10.1"
current_version = "1.11"
if Decimal(request_version) > Decimal(current_version):
pass
However, I get this error, why?
InvalidOperation at /api/version/
[<class 'decimal.ConversionSyntax'>]
You're trying to convert your version string to a float, which fails because 1.2.3 is not a valid float.
What you probably want for this kind of things is the packaging package, which implements the PEP 440 version semantics (among other niceties):
>>> from packaging.version import parse
>>> request_version = parse("1.10.1")
>>> current_version = parse("1.11")
>>> request_version > current_version
False
>>> request_version < current_version
True
This parse will create a Version object, which allows comparison between versions
You might want to use LooseVersion from distutils.version:
from distutils.version import LooseVersion as V
current = V('1.10.1')
request_version = V('1.11')
if current < request_version:
print("Yay.")
1.2.3) or something? Also, note that releases don't compare numerically -1.2is less recent than1.11, even though it's a larger number, for example.1.10.1isn't a valid number); and: 2. You're still going to hit the problem that comparing them as numbers is precisely the wrong way to do this.