PHP display mysql result based on date picker input

Question

I have two pages index4.php and generate.php. User have to select a date range and click on button in index4.php to generate user report in generate.php.

index4.php

database table

And I wish to display those results in generate.php something like this:

Here is my coding for both pages:
index4.php

<form action="generate.php" method="post" target="_blank">
    <table width="528" align="center" boder="0">
    <tr>
        <td width="109">Select date :</td>
        <td width="202">FROM&nbsp;&nbsp;<input type="date" name="start_date" required/></td>
        <td width="24">TO</td>
        <td width="173">&nbsp;<input type="date" name="end_date" required/></td>
    </tr>
    <tr>
        <td colspan="4"><i><font color="#FF0000">*</font>&nbsp;Required field.</i></td>
    </tr>
    <tr>
    <td colspan="4" align="center"><input type="submit" value="Generate User Report"/></td>
    </tr>
    </table>
</form>

generate.php

<table align="center" border="1">
<tr>
    <td align="center">Date</td>
    <td align="center">Page Name</td>
    <td align="center">Page Viewed</td>
</tr>
<?php
    if(mysql_num_rows($select_page_view) > 0)
    {
        $row = mysql_fetch_array($select_page_view); ?>
        <tr>
            <?php $num_rows = mysql_num_rows($select_page_view); ?>
            <td rowspan="<?php echo $num_rows; ?>"><?php echo $row['page_view_date']; ?></td>
        </tr>
        <?php
        while($row)
        {?>
            <tr>
            <td><?php echo $row['page_name'];?></td><td><?php echo $row['visited_times']; ?></td>
            </tr>
  <?php } ?>
<?php }?>
</table>

When I test my generate.php and the page shows infinite loop for page_name... any solution to solve it?

You need to stop using mysql_ functions as they are removed in PHP7 — Machavity
– Machavity ♦, Commented Mar 8, 2016 at 14:03

fusion3k · Accepted Answer · 2016-03-08 13:57:26Z

1

You have to change the loop in this way:

while( $row = mysql_fetch_array($select_page_view) )
{
    (...)
}

In your original syntax:

$row = mysql_fetch_array($select_page_view);
(...)
while( $row )
{
    (...)
}

$row is fetched one, then it doesn't change, so the loop doesn't stop.

answered Mar 8, 2016 at 13:57

fusion3k

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