Generate a random char, oracle

Question

I have a table with a column like: A1 A2 . . B1 .. B7

I need to generate this column randomly. This column type is CHAR(2). I tried using TRUNC(dbms_random.value(65,67)) and then ascii function for the letter part of the char but it has not worked. Can you please help me generate A1-A7, B1-B7 randomly?

dnoeth · Accepted Answer · 2016-03-12 09:00:23Z

1

You need the CHR funciton instead of ASCII, this should work:

   CHR(TRUNC(dbms_random.value(65,67)))  -- A..B
|| CHR(TRUNC(dbms_random.value(49,56)))  -- 1..7

answered Mar 12, 2016 at 9:00

dnoeth

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