Java: Array with loop(matches)

Question

I need to find the first match in this task. Probably i am just missing something. As you can see, i found the last match.I am not copied the first half of the code. Thank you.

for (int i = 0; i <= n - 1; i++) {
    if (iv[i] == a) {
        hely = i;
    }
}
if (hely == -1) {
    System.out.println("text");
} else {
    System.out.println("text " + a + " text " + (hely + 1) + "text");
}

You just need to exit out of your loop when you find a first match, no need to continue looping after first match. — amit28
– amit28, Commented Mar 12, 2016 at 13:16

Madhawa Priyashantha · Accepted Answer · 2016-03-12 13:02:05Z

2

break the loop when you find first match.

for (int i = 0; i <= n - 1; i++) {
    if (iv[i] == a) {
        hely = i;
        break;
    }
}

answered Mar 12, 2016 at 13:02

Madhawa Priyashantha

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Comments

nicomp · Accepted Answer · 2016-03-12 13:02:06Z

2

You need to exit the for loop after finding the first match:

for (int i = 0; i <= n - 1; i++) {
    if (iv[i] == a) {
        hely = i;
        break;
    }
}

answered Mar 12, 2016 at 13:02

nicomp

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