How can I convert a Clojure namespace to a string?

Question

I'm trying to pretty print a list of namespaces:

(doseq [x (all-ns)] (println x))

This prints each namespace as #<Namespace xxxxx>. I would like to get each namespace as xxxxx (that is without the #<Namespace>. I tried to (name x), (symbol x) but I get ClassCastException clojure.lang.Namespace cannnot be cast to java.lang.Named, etc.

(doseq [x (all-ns)] (println (name x)))
(doseq [x (all-ns)] (println (str x)))
(doseq [x (all-ns)] (println (namespace x)))

How can I get the namespace as a string?

I realized that actually (doseq [x (all-ns)] (println (str x))) does work, I did have a typo when I tried. But ns-name as pointed in the answers is the function to use, better than str — RubenLaguna
– RubenLaguna, Commented Mar 14, 2016 at 20:36

Sven Schoenung · Accepted Answer · 2016-03-14 20:35:14Z

7

Use ns-name:

(doseq [x (all-ns)] (println (ns-name x)))

Note that ns-name gives you a symbol. So if you want a string just use (str (ns-name ns)).

edited Mar 14, 2016 at 20:35

answered Mar 14, 2016 at 20:29

Sven Schoenung

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Bob Jarvis - Слава Україні · Accepted Answer · 2016-03-14 20:30:04Z

2

Use the ns-name function:

(doseq [x (all-ns)] (println (ns-name x)))

Namespace function docs can be found here

Best of luck.

answered Mar 14, 2016 at 20:30

Bob Jarvis - Слава Україні

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