Im having trouble trying to get this to work.
<?php
$_SESSION['age'] = 11
if($_SESSION['age'] < 14) {
echo "<h2>Your only $_SESSION['age']? Thats Young!</h2>";
}
?>
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1 Answer
If you want to echo PHP variable inside echo function, you must as first break echo with ", then add a "merge char" ., then your variable and then again "merge char" and ".
Also don't forget to add semicolon to end of your line which contains definition of $_SESSION['age'].
Edit your code to:
<?php
$_SESSION['age'] = 11;
if($_SESSION['age'] < 14) {
echo "<h2>Your only ".$_SESSION['age']."? Thats Young!</h2>";
}
?>
8 Comments
devpro
$_SESSION['age'] = 11 syntax error
pes502
add
; to end of your line with $_SESSION['age'] = 11 (edited in my code)devpro
good, also mention one more point, make sure you are using session_start(); otherwise it will not work.
gavgrif
if you are using session variables, shouldn't you be GETTING the $_SESSION['age'] variable instead of SETTING it? (for example $age = $_SESSION['age']); Otherwise there is no benefit in referencing the $_session variables.
Bailey Warrick
Also, this wasn't my full code. I'm making a quick game using html forms and php. The age is defined elsewhere on a different page :P. I just added the "$_SESSION['age' = 11;" for reference.
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