String concatenation error? [PHP]

Question

i want to upload and then move a video to a directory i just created. Instead of moving the video to /var/www/html/ProductVideos/[email protected] it sends the video to /var/www/html/ProductVideos/

It works if i make $location = "/var/www/html/ProductVideos/[email protected]" but the location will change so i am trying to make the PHP script dynamic

ProductAccountName = [email protected]

Before PHP:

After PHP:

PHP code:

<?php

$ProductAccountName = $_POST['ProductAccountName'];

$NewDirectory = "/var/www/html/ProductVideos/" . $ProductAccountName;

if (!file_exists($NewDirectory))
    {
        mkdir($NewDirectory, 0777, true);
    }

if($_SERVER['REQUEST_METHOD']=='POST'){
$file_name = $_FILES['myFile']['name'];
$file_size = $_FILES['myFile']['size'];
$file_type = $_FILES['myFile']['type'];
$temp_name = $_FILES['myFile']['tmp_name'];

$location = $NewDirectory . $file_name; //"/var/www/html/ProductVideos/$ProductAccountName/" . $file_name;

move_uploaded_file($temp_name, $location);

Zamrony P. Juhara · Accepted Answer · 2016-03-15 08:34:36Z

1

Maybe $_POST['ProductAccountName'] is not set, so following code

$ProductAccountName = $_POST['ProductAccountName'];

$NewDirectory = "/var/www/html/ProductVideos/" . $ProductAccountName;

causes $ProductAccountName to be empty. Make sure you add

<input type="text" name="ProductAccountName" value="[email protected]">

inside your HTML form.

answered Mar 15, 2016 at 8:34

Zamrony P. Juhara

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4 Comments

Lazar Kukolj Over a year ago

well if that was the case then the new directory wouldnt be made

Zamrony P. Juhara Over a year ago

try print($location); just to make sure it points to correct directory.

Lazar Kukolj Over a year ago

i am actually not using HTML so i couldnt do that :/

Lazar Kukolj Over a year ago

This isnt the correct answer but it got me thinking and i figured it out myself

aslawin · Accepted Answer · 2016-03-15 08:34:24Z

0

I think there is no / after $ProductAccountName in creating $NewDirectory variable. Try rewerite location like this:

$location = $NewDirectory . '/' . $file_name;

answered Mar 15, 2016 at 8:34

aslawin

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2 Comments

Lazar Kukolj Over a year ago

i think its something like that but that didnt fix it

aslawin Over a year ago

So what is in $location variable?

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