Calling variable from another function

Question

The function below gives me this error:

"UnboundLocalError: local variable 'housebank' referenced before assignment"

def placeBet(table, playerDictionary, bet, wager):
    playerDictionary['You'][1].add(bet)
    housebank -= (wager*table[bet][0])
    table[bet][1]['You']=wager

The housebank variable is declared in my main function below:

def main():
    housebank = 1000000
    table = {'7' : [9/1,{}]}
    playerDirectory = {'player1':[1,set(),True]}
    placeBet(table,playerDirectory, 10, 100)

How can I use housebank in the placeBet function? If I do a return it will exit the main function, which I do not want to do... Any ideas?

Amadan · Accepted Answer · 2016-03-16 10:09:59Z

1

housebank is local to placeBet. There's three ways to do it that I can see:

Make a class.

class Foo:
    def __init__():
        self.housebank = 1000000
    def run():
        # ....
    def placeBet(....):
        # ....
        self.housebank -= (wager*table[bet][0])
        # ....

def main():
    Foo().run()

Declare housebank in a wider scope:

housebank = 1000000
def placeBet(....):
    # ....
def main():
    # ....

Make placeBet a closure inside main:

def main():
    housebank = 1000000
    def placeBet(....):
        # ....
    # .... rest of main ....

answered Mar 16, 2016 at 10:09

Amadan

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1 Comment

ZigZag Over a year ago

Thank you. This is exactly what I was looking for!

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