Getting the file path from file name in java

Question

To get the file path from file name in directory I have src/test/resources/datasheets directory.

src/test/resources/datasheets
xyz/a1.txt
abc/b1/txt

It has many directories again

I need to get the file path If i give the file name ex : "a1.txt" I need to get as src/test/resources/datasheets/xyz/a1.txt

Thanks in advance

Can you show us the code you are using so we can see where you might be having difficulty? How to create a Minimal, Complete, and Verifiable example — pczeus
– pczeus, Commented Mar 18, 2016 at 21:35
Are you running tests from something like maven, which defines a directory for test resources as src/test/resources? If so, when running your tests, the resources would get copied into the build directory, and the path to the a1.txt resource would actually only be datasheets/xyz/a1.txt — AJNeufeld
– AJNeufeld, Commented Mar 18, 2016 at 21:44

rdonuk · Accepted Answer · 2016-03-18 22:01:05Z

Just write a recursive method to check all sub directories. I hope that will work:

import java.io.File;

public class PathFinder {

    public static void main(String[] args) {
        String path = getPath("a1.txt", "src/test/resources/datasheets");
        System.out.println(path);
    }

    public static String getPath(String fileName, String folder) {
        File directory = new File(folder);

        File[] fileList = directory.listFiles();
        for (File file : fileList) {
            if (file.isFile()) {
                if(fileName.equals(file.getName())) {
                    return file.getAbsolutePath();
                }
            } else if (file.isDirectory()) {
                String path = getPath(fileName, file.getAbsolutePath());
                if(!path.isEmpty()) {
                    return path;
                }
            }
        }

        return "";
    }
}

Debosmit Ray · Accepted Answer · 2016-03-18 21:41:59Z

0

This information is easily accessible if you had referred to the [File docs].

File myDir = File(String pathname);
if(myDir.isDirectory()) {
    File[] contents = myDir.listFiles(); 
}

See what your contents[] looks like and make necessary modifications.

answered Mar 18, 2016 at 21:41

Debosmit Ray

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