How to use multiple bash commands in single lines

Question

OS: Linux RedHat

Bash: 3.5

I have 2 commands below to get list of files with status of them and another command for footprint. I want to find the way to combine them together in single line.

Here's my mentioned commands.

find "$PWD" -type f ! -iname '*thumbs.db*' -print0 | xargs -0 stat -c "%y %s %n"
find "$PWD" -type f -print0 | xargs -0 sha1sum -b

helloV · Accepted Answer · 2016-03-21 04:26:26Z

1

Will this work? Do a man on xargs.

find $PWD -type f ! -iname '*thumbs.db*' -print0 | xargs -0 -I '{}' sh -c 'stat --printf "%y %s %n " {} ; sha1sum -b {}'

If you do not want the file name repeated twice:

find $PWD -type f ! -iname '*thumbs.db*' -print0 | xargs -0 -I '{}' sh -c 'stat --printf "%y %s %n " {} ; sha1sum -b {} | cut -d\  -f1'

There needs to be 2 blank spaces after d\ in cut command.

edited Mar 21, 2016 at 4:26

answered Mar 21, 2016 at 4:18

helloV

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1 Comment

NNOPP Over a year ago

it's works, but didn't put the result together as list sheet.

Subin · Accepted Answer · 2016-03-21 06:37:44Z

0

You can do this with -exec in find command itself.

find $PWD -type f ! -iname '*thumbs.db*' -exec stat -c "%y %s %n" {} \; -exec sha1sum -b {} \;

answered Mar 21, 2016 at 6:37

Subin

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