Can anyone help how to click the below link using selenium
<a class=”btn btn-primary btn-large” href="target-URL">Submit</a>
I tried using below options
- linkText
- partialLinkText
- CssSelector
- contains - logic which checks the URL text
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tony, is the given answers worked for u?noor– noor2016-03-23 08:24:22 +00:00Commented Mar 23, 2016 at 8:24
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4 Answers
You can try:
driver.findElement(By.xpath("//a[contains@class,'btn '] and contains(@class, 'btn-large') and contains(text(), 'Submit')")).click()
1 Comment
Tony
Thanks. It worked. But i changed the parenthesis driver.findElement(By.xpath("//a[contains(@class,'btn ') and contains(@class, 'btn-large') and contains(text(), 'Submit')]")).click();
Give full xpath
driver.findElement(By.xpath("html/body/a").click();
Can try with tag name
driver.findElement(By.tagName("a").click();
Comments
Try with below xpath:
driver.findElement(By.xpath("//a[@href='target-URL']").click();
Comments
In theory, this is just:
driver.findElment(By.linkText("Submit")).click();
But, I'm pretty sure you've already tried that. Check if the element is in iframe/frame. If yes, you need to switch to it and only then find the link element:
driver.switchTo().frame("frame_name_or_id");
To switch back in the main context, use defaultContent():
driver.switchTo().defaultContent();
1 Comment
Tony
I tried that it didn't work for me. I am using firefox webdriver