Php echo $_POST with a variable

Question

I'm trying to display a $_POST that has a variable within.

Here's my PHP code:

<?php if ($options) { ?>
<?php foreach ($options as $option) { ?>
<?php if ($option['type'] == 'select') { ?>
<textarea name="<?php echo $option['name']; ?>" rows="1" cols="20" class=""><?php echo '$_POST['.$option['name'].']' ?></textarea>
<?php } ?>
<?php } ?>
<?php } ?>

So far I'm able to display the $option['name'] variable.So, for <?php echo '$_POST['.$option['name'].']' ?>, I get $_POST[size] for exemple in the textarea.

Any idea how to work this out?

Pupil · Accepted Answer · 2016-03-30 09:44:11Z

1

Variables inside single quotes are not parsed due to variable interpolation.

What you can do is:

Replace

<?php echo '$_POST['.$option['name'].']' ?>

By

<?php echo $_POST[$option['name']]; ?>

answered Mar 30, 2016 at 9:44

Pupil

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Comments

Maninderpreet Singh · Accepted Answer · 2016-03-30 09:44:18Z

1

I found error between textarea

change this line

<?php echo '$_POST['.$option['name'].']' ?>

to this

<?php echo $_POST[$option['name']] ?>

answered Mar 30, 2016 at 9:44

Maninderpreet Singh

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Comments

Mahendra Salve · Accepted Answer · 2016-03-30 09:47:29Z

1

Use this line

 <?php echo $_POST[$option['name']] ?>

answered Mar 30, 2016 at 9:47

Mahendra Salve

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Comments

Brogan · Accepted Answer · 2016-03-30 10:06:39Z

0

Try this:

<?php
if($options) {
    foreach($options as $option) {
        if($option['type'] == 'select')
            echo '<textarea name="', $option['name'], '" rows="1" cols="20">', $_POST[$option['name']], '</textarea>', "\n";
    }
}

answered Mar 30, 2016 at 10:06

Brogan

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