Printing and parsing JSON variable in PHP

Question

I've the following PHP code with a JSON variable...

$route_geometry_json = "{
    \"route_geometry\": [
        [44.911537, 7.671326],
        [44.911481, 7.671462],
        [44.911455, 7.671531],
        [44.911434, 7.671602],
        [44.911358, 7.671859],
        [44.911273, 7.672175],
        [44.911198, 7.672458],
        [44.91113, 7.672617],
        [44.911069, 7.67275],
        [44.911003, 7.672821],
        [44.910945, 7.672881],
        [44.910869, 7.672954],
        [44.910868, 7.673046],
        [44.91091, 7.673109],
        [44.91095, 7.67319],
        [44.910964, 7.673266],
        [44.910958, 7.673407],
        [44.910955, 7.6735],
        [44.910947, 7.673632],
        [44.910922, 7.673871],
        [44.910828, 7.674786],
        [44.910711, 7.675816],
        [44.910606, 7.676364],
        [44.910467, 7.676322],
        [44.910368, 7.676308],
        [44.910051, 7.676253],
        [44.9097, 7.676162],
        [44.90944, 7.676041],
        [44.909297, 7.675958],
        [44.909174, 7.67583],
        [44.909107, 7.675722],
        [44.908993, 7.675583],
        [44.908758, 7.675448],
        [44.90796, 7.675037]
    ]
  }";

print "Route geometry -->" + json_encode($route_geometry_json);

The print return "0": any suggestion / example?

I'd like also to extract / print the coords couples like

    44.908993, 7.675583
    44.908758, 7.675448

Any suggestion will be appreciated ...

Thanks

Cesare

yep, encode converts a value to json, while decode converts a json to a variable — philoniare
– philoniare, Commented Mar 31, 2016 at 12:12

Md Mahfuzur Rahman · Accepted Answer · 2016-03-31 12:21:13Z

1

Use this code:

$route_geometry = json_decode($route_geometry_json);

foreach ($route_geometry->route_geometry as $value) {
    echo $value[0].', '.$value[1].'<br />';
}

answered Mar 31, 2016 at 12:21

Md Mahfuzur Rahman

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Comments

Parthapratim Neog · Accepted Answer · 2016-03-31 13:06:08Z

1

You need to print_r(json_decode($route_geometry_json)) it and not json_encode

json_encode is for creating a JSON string. But since you already have a JSON string already, you need to Decode it to make it an Array/Object.

UPDATE

Your requirement

echo "Route geometry -->"; 
print_r(json_decode($route_geometry_json));

You cannot concat a String and an Object, so you were getting that Parse error.

edited Mar 31, 2016 at 13:06

answered Mar 31, 2016 at 12:10

Parthapratim Neog

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9 Comments

Cesare Over a year ago

Thanks! I've tried but the result is ..... "Notice: Object of class stdClass could not be converted to int ....." :-(

Parthapratim Neog Over a year ago

use print_r to print

Cesare Over a year ago

I've tried to use "print_r" to print and now the error is "Parse error: syntax error, unexpected '"Route geometry -->"' (T_CONSTANT_ENCAPSED_STRING)" ....

Parthapratim Neog Over a year ago

remove the back slashes from the string and it should work ... "route_geometry" and use single quotes for the whole string. Try

Parthapratim Neog Over a year ago

Because you cannot concat, a string and a Object as one. So, print them differently.

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