Suppose I want to create a list or a numpy array of 5 elements like this:
array = [i, j, k, l, m]
where:
i is in range 1.5 to 12.4j is in range 0 to 5k is in range 4 to 16l is in range 3 to 5m is in range 2.4 to 8.9.This is an example to show that some ranges include fractions. What would be an easy way to do this?
You can just do (thanks user2357112!)
[np.random.uniform(1.5, 12.4), np.random.uniform(0, 5), ...]
using numpy.random.uniform.
np.random.uniform.
I would suggest generating them by hand and create the list later:
import numpy as np
i = np.random.uniform(1.5, 12.4)
j = np.random.randint(0, 5) # 5 not included use (0, 6) if 5 should be possible
k = np.random.randint(4, 16) # dito
l = np.random.randint(3, 5) # dito
m = np.random.uniform(2.4, 8.9.)
array = np.array([i, j, k, l, m]) # as numpy array
# array([ 3.33114735, 3. , 14. , 4. , 4.80649945])
array = [i, j, k, l, m] # or as list
# [3.33114735, 3, 14, 4, 4.80649945]
If you want to create them all in one go you can use np.random.random use the range and the lower-bound to modify them and convert them to integer where you don't want floats:
# Generate 5 random numbers between 0 and 1
rand_numbers = np.random.random(5)
# Lower limit and the range of the values:
lowerlimit = np.array([1.5, 0, 4, 3, 2.4])
dynamicrange = np.array([12.4-1.5, 5-0, 16-4, 5-3, 8.9-2.4]) # upper limit - lower limit
# Apply the range
result = rand_numbers * dynamicrange + lowerlimit
# convert second, third and forth element to integer
result[1:4] = np.floor(result[1:4])
print(result)
# array([ 12.32799347, 1. , 13. , 4. , 7.19487119])
import random
array = [random.uniform(1.5, 12.4), random.uniform(0,5)]
print(array)
prints:
[9.444064187694842, 1.2256912728995506]
You might want to round these with round()
np.randomfunctions and stick the results in an array.