Recursive directory iterator get filepath of file with subfolders

Question

I have a function that recursively iterates over a directory tree. This works fine, I get a array returned with the directories and files.

$dir = 'files';
function dirToArray($dir) { 
   
   $result = array(); 

   $cdir = scandir($dir); 
   foreach ($cdir as $key => $value) {

      if (!in_array($value,array(".",".."))) { 
         if (is_dir($dir . DIRECTORY_SEPARATOR . $value)) { 
            $result[$value] = dirToArray($dir . DIRECTORY_SEPARATOR . $value); 
         } 
         else { 
            $result[] = $value;
         } 
      } 
   } 

   return $result; 
}

I then iterate recursively over the returned array to display a nice menu structure to the user, which also works fine.

function printAll($arr) {

    if(!is_array($arr)) {
        echo '<li><div class="sub_menu_path"></div><a href="'.$arr.'" class="file"><i class="fa fa-fw fa-file-text-o"></i>'.$arr.'</a></li>';
    }
    else {
    
        foreach($arr as $k => $v) {

            if(is_array($v)) {  
                echo '<li><div class="sub_menu_path"></div><a href="'.$k.'" class="multi_menu folder"><i class="fa fa-fw fa-folder-o"></i>'.$k.'</a>';                          

                echo '<ul class="sub_menu">';                               
                    printAll($v);                               
                echo '</ul>';

                echo '</li>';
            }
            else {
                echo '<li><div class="sub_menu_path"></div><a href="'.$v.'" class="file"><i class="fa fa-fw fa-file-text-o"></i>'.$v.'</a></li>';                                   
            }
        }
    }
}               

printall(dirToArray($dir));

result:

but what I want is when I display the file to the user wrapped in an html <a href="$value">$value</a> how to get the complete path including subfolders? for example: files/Products/Cress/Ramnunculus/Introduction/file.txt I only get file.txt so when I click in file.txt it says file not found of course.

EDIT (Solution):

as suggested in the answer, I added a extra parameter. I changed the variable $v to $k because it gives a array to string conversion.

function printAll($arr, $path = '') {
    if(!is_array($arr)) {
        echo '<li><div class="sub_menu_path"></div><a href="'.$arr.'" class="file"><i class="fa fa-fw fa-file-text-o"></i>'.$arr.'</a></li>';
    }
    else {
    
        foreach($arr as $k => $v) {

            $file_path = $path . ($path == '' ? '' : '/') . $k;
            
            if(is_array($v)) {  
                echo '<li><div class="sub_menu_path"></div><a href="" class="multi_menu folder"><i class="fa fa-fw fa-folder-o"></i>'.$k.'</a>';

                echo '<ul class="sub_menu">';                               
                    printAll($v, $file_path);                               
                echo '</ul>';

                echo '</li>';
            }
            else {
                echo '<li><div class="sub_menu_path"></div><a href="'.$file_path.'" class="file"><i class="fa fa-fw fa-file-text-o"></i>'.$v.'</a></li>';                                   
            }
        }
    }
}               
    
printall(dirToArray($dir));

Siffer · Accepted Answer · 2016-04-06 11:55:03Z

2

Include optional parameter $path = ''

    function printAll($arr, $path = '') {

        if(!is_array($arr)) {
            $file_path = $path . ($path == '' ? '' : '/') . $arr;
            echo '<li><div class="sub_menu_path"></div><a href="'.$file_path.'" class="file"><i class="fa fa-fw fa-file-text-o"></i>'.$arr.'</a></li>';
        }
        else {

            foreach($arr as $k => $v) {
                if(is_array($v)) {
                    $file_path = $path . ($path == '' ? '' : '/') . $k;

                    echo '<li><div class="sub_menu_path"></div><a href="'.$file_path.'" class="multi_menu folder"><i class="fa fa-fw fa-folder-o"></i>'.$k.'</a>';

                    echo '<ul class="sub_menu">';
                    printAll($v, $file_path);
                    echo '</ul>';

                    echo '</li>';
                }
                else {
                    $file_path = $path . ($path == '' ? '' : '/') . $v;
                    echo '<li><div class="sub_menu_path"></div><a href="'.$file_path.'" class="file"><i class="fa fa-fw fa-file-text-o"></i>'.$v.'</a></li>';
                }
            }
        }
    }

edited Apr 6, 2016 at 11:55

answered Apr 6, 2016 at 11:22

Siffer

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2 Comments

Julez Over a year ago

Edit: i changed $v to $k and now it works. thank alot man. dindt know it was so easy.

Siffer Over a year ago

You peat me to it, changed my code to properly work with your array structure :) Cheers!

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