How to upload base64 image by creating directory and upload

Question

I am want to upload image into following folder structure:

/var/www/html/project/public/upload/userimage/2016/04/07/thumbnail/image.png
                                               ^   ^  ^
                                            Year Month Date

and I have wrote this code:

$Day = date('d'); // Get date
$Month = date('m'); // Get month
$Year = date('Y'); // Get year

$data = $_POST['base64']; // Get base64 image data

$imageName = hash('ripemd160', time()).'.png';

if (!file_exists(public_path().'/upload/userimage/'.$Year.'/'.$Month.'/'.$Day.'/thumbnail')) {
    mkdir(public_path().'/upload/userimage/'.$Year.'/'.$Month.'/'.$Day.'/thumbnail', 0777, true);
}
$url = public_path().'/upload/userimage/'.$Year.'/'.$Month.'/'.$Day.'/thumbnail/'.$imageName;

list($type, $data) = explode(';', $data);
list(, $data)      = explode(',', $data);
$data = base64_decode($data);
file_put_contents($url.'/'.$imageName, $data);

and getting this error:

file_put_contents(/var/www/html/project/project/public/upload/userimage/2016/04/07/thumbnail/8b38eb25ce97d428afcd80d6ddcd16b8ca266a52.png/8b38eb25ce97d428afcd80d6ddcd16b8ca266a52.png): failed to open stream: No such file or directory

I just want to upload image to directory folder with generating folder Year -> Month -> Date if Year/Month/Date is changed.

I will appreciate if you help me to make my code more proper :)

Thanks.

I dunno whether it works, but once try creating the directory first using mkdir function and then upload files into it. — phpfresher
– phpfresher, Commented Apr 7, 2016 at 9:25

fusion3k · Accepted Answer · 2016-04-07 09:38:32Z

Yes, your directory doesn't exists.

$url = public_path().'/upload/userimage/'.$Year.'/'.$Month.'/'.$Day.'/thumbnail/'.$imageName;
#                                                                                 ----------
file_put_contents($url.'/'.$imageName, $data);
#                          ----------

You create this directory:

/My/New/Directory

Then you try to write this file:

/My/New/Directory/Image.jpg/Image.jpg

Use this command:

file_put_contents( $url , $data );

A general suggestion: use variables instead of repeat concatenate patterns, especially if you have long concatenations. Your code is more clear, code maintenance is easier and the risk of typos is lower:

$dirPath = public_path().'/upload/userimage/'.$Year.'/'.$Month.'/'.$Day.'/thumbnail';
if( !file_exists( $dirPath ) )      
    mkdir( $dirPath, 0777, true );
}
$filePath = $dirPath.'/'.$imageName;
(...)
file_put_contents( $filePath , $data );

Community · Accepted Answer · 2017-05-23 11:50:38Z

1

file_put_contents does not create directory: So use:

if (!is_dir('upload/usersimage/'.$Year.'/'.$Month.'/'.$Day.'' . $month)) {
    mkdir('upload/usersimage/'.$Year.'/'.$Month.'/'.$Day.' . $month);
}

See here: Creating a folder when I run file_put_contents()

edited May 23, 2017 at 11:50

CommunityBot

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answered Apr 7, 2016 at 9:27

Axel Couturier

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