Looking to assign print output (string) to a variable

Question

I've been struggling for the past 2 days to do something that I am sure is easy. Unfortunately I do not know python very well (nearly nothing actually) and I'm just trying to edit a script for work.

Basically it should look into a folder, get the filename and assign the filename to a variable. But everything I tried failed :

filepath = "/folder/*.*/"
for path in glob.glob(filepath):
  dirname, filename = os.path.split(path)
  print(filename)[0:-19]

var1 = filename
var2 = filename[0:-25]

I tried with

var1 = str(filename)

But nothing works. Any advice would be greatly appreciated!

I don't get what you are trying to do with [0:-19] and [0:-25]. Without it I manage to get all filenames present in all matching folders (easily editable to save the names into variables). If it's what you want, I can put the answer. — David Guyon
– David Guyon, Commented Apr 7, 2016 at 14:33

Jack Geller · Accepted Answer · 2016-04-07 14:28:01Z

1

def GetFileList(FindPath,FlagStr=[]):  
    ''''' 
    #>>>FlagStr=['F','EMS','txt'] # Characters need to include
    #>>>FileList=GetFileList(FindPath,FlagStr) # 
    '''  
    import os  
    FileList=[]  
    FileNames=os.listdir(FindPath)  
    if (len(FileNames)>0):  
        for fn in FileNames:  
            if (len(FlagStr)>0):  
                #return Specified filename  
                if (IsSubString(FlagStr,fn)):  
                    fullfilename=os.path.join(FindPath,fn)  
                    FileList.append(fullfilename)  
            else:  
                #return all filename  
                fullfilename=os.path.join(FindPath,fn)  
                FileList.append(fullfilename)  

     #sort filename
     if (len(FileList)>0):  
         FileList.sort()  

     return FileList

answered Apr 7, 2016 at 14:28

Jack Geller

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Comments

n1c9 · Accepted Answer · 2016-04-07 14:34:44Z

0

The way that your code is written now, it prints however many file names for the number of files in your folder, discards the filename variable and runs again on a new path. When you have a for loop, the variables are discarded on every iteration to make way for the new ones. So this code:

filepath = "/folder/*.*/"

for path in glob.glob(filepath):
    dirname, filename = os.path.split(path)
    print( filename )[0:-19]

Var1 = filename
Var2 = filename[0:-25]

is running for each path you supply it with initially, then keeps only the last filename when you refer back to it in the vars. I think what you want is something like this:

for path in filepath:
  dirname, filename = os.path.split(path)
  print(filename[0:-19])
  var1 = filename
  var2 = filename[0:-25]

From there, you could do anything you want with var1 and var2.

answered Apr 7, 2016 at 14:34

n1c9

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2 Comments

Ciarán Over a year ago

That did it !Thank you very much !

n1c9 Over a year ago

Glad I could help!

jDo · Accepted Answer · 2016-04-07 14:30:57Z

0

It might be a simple indentation issue. Currently, var1 and var2 are outside the for loop. I didn't study your script or its output thoroughly but doing what I've done below will assign the value of filename to var1 and assign a section of filename (from the beginning to the character 25 places from the end) to var2.

filepath = "/folder/*.*/"
for path in glob.glob(filepath):
  dirname, filename = os.path.split(path)
  print(filename)[0:-19]
  var1 = filename
  var2 = filename[0:-25]
  print(var1)
  print(var2)

answered Apr 7, 2016 at 14:30

jDo

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Comments

Filip · Accepted Answer · 2016-04-07 14:35:01Z

0

Try this and work from there:

import os

filepath = "/"

var1 = os.listdir(filepath)
var2 = os.listdir(filepath)[2]

print var1
print
print var2

answered Apr 7, 2016 at 14:35

Filip

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