I study Java as a subject in college and I got this code in the sheet to get the output, I executed the code to get the result of (11).
int i;
for (i=1; i<10; i+=2);
System.out.println(i);
But what does it really do?
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2Note the semicolon after the for.Luan Nico– Luan Nico2016-04-09 18:11:18 +00:00Commented Apr 9, 2016 at 18:11
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One of the best arguments I know for always using the opening and closing braces, even if it's a loop body with one line. IntelliJ would have caught this blooper.duffymo– duffymo2016-04-09 18:18:30 +00:00Commented Apr 9, 2016 at 18:18
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3 Answers
Let's start at the beginning, declare a variable named i of type int.
int i;
Now we shall loop, initialize i to the value 1, while i is less than 10 add 2 to i (1, 3, 5, 7, 9, 11). 11 is not less than 10 so stop looping.
for (i=1; i<10; i+=2);
Finally, print i (11).
System.out.println(i);
Comments
Someone is being sneaky. Here's how it would lay out indented norrmally:
int i;
for (i=1; i<10; i+=2)
;
System.out.println(i);
int i; declares a variable named i of type int.
for (i=1; i<10; i+=2)
;
is a for loop that starts by setting i to 1, and then loops while i is less than 10, adding 2 toi` each time. The semicolon after the for is a no-op, an empty statement.
Try this version and see what happens:
int i;
for (i=1; i<10; i+=2)
System.out.println(i);
System.out.println(i);
Comments
The code could be written more clearly like this (I will include comments denoting what each section does):
//declare a number variable
int i;
//this is a for loop
//the first part sets i to 1 to begin with
//the last part adds 2 to i each time
//and the middle part tells it how many times to execute
//in this case until i is no longer less than 10
for (i = 1; i < 10; i+=2);
//this prints out the final value, which is 11
System.out.println(i);
So your code will start i at 1 and then loop i = 3, i = 5, etc. until i is no longer less than 10 which happens when i = 9, i = 11 Then the program stops and you print the final value of i
Comments
