I want to serialize/deserialize following classes into/from JSON:
public class Employee
{
string name;
Position position;
}
public class Position
{
string positionName;
int salary;
}
The tricky part is that I want to treat Position fields as Employee fields, so JSON would look like this:
{
"name": "John",
"positionName": "Manager",
"salary" : 1000
}
How to achieve this using Json.NET ?
You have either to deserialize it as anonymous object either (recommended ) implement a custom deserialization as stated here:
Merge two objects during serialization using json.net?
Please let us know if there any more questions.
Here's an example (you can find it in the provided link):
public class FlattenJsonConverter : JsonConverter
{
public override void WriteJson(JsonWriter writer, object value,
JsonSerializer serializer)
{
JToken t = JToken.FromObject(value);
if (t.Type != JTokenType.Object)
{
t.WriteTo(writer);
return;
}
JObject o = (JObject)t;
writer.WriteStartObject();
WriteJson(writer, o);
writer.WriteEndObject();
}
private void WriteJson(JsonWriter writer, JObject value)
{
foreach (var p in value.Properties())
{
if (p.Value is JObject)
WriteJson(writer, (JObject)p.Value);
else
p.WriteTo(writer);
}
}
public override object ReadJson(JsonReader reader, Type objectType,
object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
public override bool CanConvert(Type objectType)
{
return true; // works for any type
}
}
My solution is this
static void Main(string[] args)
{
Position p = new Position();
p.positionName = "Manager";
p.salary = 1000;
Employee e = new Employee();
e.name = "John";
e.position = p;
ResultJson r = new ResultJson();
r.name = e.name;
r.positionName = e.position.positionName;
r.salary = e.position.salary;
var result = JsonConvert.SerializeObject(r);
Console.WriteLine(result);
Console.ReadLine();
}
}
public class Employee
{
public string name { get; set; }
public Position position { get; set; }
}
public class Position
{
public string positionName { get; set; }
public int salary { get; set; }
}
public class ResultJson
{
public string name { get; set; }
public string positionName { get; set; }
public int salary { get; set; }
}
use seperate model for result
You can use this code with NewtonSoft.Json library
[JsonObject]
public class Employee
{
[JsonProperty("name")]
string name;
[JsonProperty("positionName")]
string positionName;
[JsonProperty("salary")]
int salary;
}
Use One class instead 2, or realize own parser
try in this way. { "name": "John", "position": [{ "positionName": "Manager", "salary" : 1000 }] }
