c++ vector of pointers to functions with specific parameters

Question

if I have a function and I want to make a pointer to it with a specific parameter I can use auto but like this:

void bar(int n){std::cout << n;}
auto foo = std::bind(bar, 2);

but if I want to make a vector of these pointers it doesn't work

std::vector<auto> v;

You're not making a pointer to a function. You're creating a bind-expression. You cannot (easily) make a container of bind-expressions, but you can make a vector of std::function<void()>. — Kerrek SB
– Kerrek SB, Commented Apr 12, 2016 at 23:34

M.M · Accepted Answer · 2016-04-12 23:50:36Z

2

You could write vector<decltype(foo)> v; although that probably doesn't do what you want (other bind expressions may give incompatible types).

As mentioned in comments, std::function is designed for this purpose:

std::vector< std::function<void()> > v;

v.emplace_back( foo );
v.emplace_back( std::bind(bar, 2) );
v.emplace_back( []{ std::cout << 2; } );

answered Apr 12, 2016 at 23:50

M.M

143k26 gold badges224 silver badges400 bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1