Javascript Window.Onload Function Chaining

Question

Just for the sake of experimentation, I've been trying to determine different ways to non-destructively chain window.onload functions in a web browser. This is the idea of what I have so far:

var load = window.onload;
var newFunction = function(){
    alert("ha!");
}
window.onload = function(){
    load();
    newFunction();
}

The problem I see with this is that every time you chain a function, it adds another level of function calls to the stack. Is there a better way to go about this that doesn't add unnecessary depth to the call stack?

maxnk · Accepted Answer · 2008-12-14 09:30:27Z

3

May be it will be better to use addEventListener/attachEvent?

Advanced event registration models

answered Dec 14, 2008 at 9:30

maxnk

5,7452 gold badges29 silver badges20 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Patryk Kordylewski · Accepted Answer · 2008-12-14 09:29:47Z

0

You could have a look at jQuery how they handle that.

From the jQuery docs:

You can have as many $(document).ready events on your page as you like. The functions are then executed in the order they were added.

answered Dec 14, 2008 at 9:29

Patryk Kordylewski

1,2691 gold badge7 silver badges11 bronze badges

Comments

Kit Sunde · Accepted Answer · 2008-12-14 09:33:39Z

0

I'd rather use the "good enough" addEvent:

var addEvent = function( obj, type, fn ) {
        if (obj.addEventListener)
                obj.addEventListener(type, fn, false);
        else if (obj.attachEvent) 
                obj.attachEvent('on' + type, function() { return fn.apply(obj, new Array(window.event));});
}

From: http://www.ilfilosofo.com/blog/2008/04/14/addevent-preserving-this/

answered Dec 14, 2008 at 9:33

Kit Sunde

37.3k29 gold badges134 silver badges179 bronze badges

Collectives™ on Stack Overflow

Javascript Window.Onload Function Chaining

3 Answers 3

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related