How to use Python and Selenium to select an extJS button

Question

The HTML is as follows:

<div id="button-1600" class="x-btn x-box-item x-toolbar-item x-btn-    default-small x-noicon x-btn-noicon x-btn-default-small-noicon" style="border-width: 1px; left: 109px; margin: 0px; top: 0px;">
<em id="button-1600-btnWrap">
<button id="button-1600-btnEl" class="x-btn-center" autocomplete="off" role="button" hidefocus="true" type="button" style="height: 14px;">
<span id="button-1600-btnInnerEl" class="x-btn-inner" style="">QA View</span>
<span id="button-1600-btnIconEl" class="x-btn-icon "></span>
</button>

I need to select the button "QA View". Since our software uses extJS, the ID # (1600) changes everytime the page is loaded. I tried using the long xpath such as follows:

DP_DEALER_SEARCH_QA_VIEW = 'html/body/div[1]/div[3]/div/div/div[2]/div/div/div/div/div/div[2]/em/button'

def click_dealerSearchQAView(self):
    webQABtn = WebDriverWait(self.driver, 10).until(
        ec.element_to_be_clickable((By.XPATH, DP_DEALER_SEARCH_QA_VIEW)))
    webQABtn.click()

I know there are ways to find this element using the shorter XPath method and things such as [Contains], but I haven't been able to figure it out. Any help is greatly appreciated.

alecxe · Accepted Answer · 2016-04-18 18:31:59Z

2

You can select it by text:

//button[. = "QA View"]

Or, to an additional parent check:

//div[starts-with(@id, "button-")]//button[. = "QA View"]

answered Apr 18, 2016 at 18:31

alecxe

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1 Comment

Jay Over a year ago

I was able to select it by the text, which is VERY useful. I will probably incorporate the parent check in the long run. It won't let me mark your answer yet, but it worked. Thank you!

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