I'm doing patterns in python but i can't seem to get a this pattern to change.
print("\nPattern C")
for c in range(1, 7 + 1):
for cc in reversed(range(1, c)):
print(cc, end = '')
print('')
This outputs:
Pattern C
1
21
321
4321
54321
654321
But i want it to output:
1
21
321
4321
54321
654321
Can anyone help please?
You will have to add spaces in some way. One way is to subtract the current counter from a fixed value and print that many spaces.
for c in range(1, 7 + 1):
print(' '*(7-c), end='')
for cc in reversed(range(1, c)):
print(cc, end = '')
print('')
As Aaron Hall mentions in comments, there are other ways to produce this output. For example, with a single print() (and num representing the 7+1 value above, and the reversed() replaced with a different range() object):
for c in range(1, num):
print(' '*(num-1-c), *range(c-1, 0, -1), sep='')
This is what i would do (while also changing your code as little as possible)
print("\nPattern C")
maxLength = 7
for c in range(1, maxLength + 1):
s = ''
for cc in reversed(range(1, c + 1)):
s += str(cc)
print(("%" + str(maxLength) + "s")%s)`
I didn't change much, I just added string formatting, and I added a "+ 1".
This uses string formatting to right justify each string.
%10s justifies a word to the end of a 10 character space.
I would use a format string method after each line to add the space padding.
print("\nPattern C")
for c in range(1, 7+ 1):
line=""
for cc in reversed(range(1, c)):
line+=str(cc)
print('{:>6}'.format(line))
N = int(input())
for i in range(N):
Num = ""
for j in range(1, i + 2):
Num = str(j) + Num
print(" " * (N - i) + (Num))
Input:-6
Output:
1
21
321
4321
54321
654321
