When I use "\n" in my print function it gives me a syntax error in the following code
from itertools import combinations
a=[comb for comb in combinations(range(1,96+1),7) if sum(comb) == 42]
print (a "\n")
Is there any way to add new line in each combination?
The print function already adds a newline for you, so if you just want to print followed by a newline, do (parens mandatory since this is Python 3):
print(a)
If the goal is to print the elements of a each separated by newlines, you can either loop explicitly:
for x in a:
print(x)
or abuse star unpacking to do it as a single statement, using sep to split outputs to different lines:
print(*a, sep="\n")
If you want a blank line between outputs, not just a line break, add end="\n\n" to the first two, or change sep to sep="\n\n" for the final option.
Two possibilities:
print "%s\n" %a
print a, "\n"
This will work for you:
I used 1,2...6 in my example and 2 length tuples with a combination sum of 7.
from itertools import combinations
a=["{0}\n".format(comb) for comb in combinations(range(1,7),2) if sum(comb) == 7]
print(a)
for thing in a:
print(thing)
['(1, 6)\n', '(2, 5)\n', '(3, 4)\n']
(1, 6)
(2, 5)
(3, 4)
for me in the past something like print("\n",a) works.
\nafterawill improve the readability... maybe you want to print a new line after each combination?for combination in a: print(combination)will do what you want.