JAVA try catch ArrayIndexOutOfBoundsException

Question

I would like to Rewrite the getContents method below to incorporate exception handling. In particular, when an ArrayIndexOutOfBoundsException is generated, the method should return the value -1.0

public class Four
{
 private double [] numbers = {1.0, 2.0, 3.0, 4.0};

 public double getContents(int index)
 {
 return numbers[index];
 }
}

user2494817 · Accepted Answer · 2016-05-02 00:00:44Z

3

public class Four
{
    private double [] numbers = {1.0, 2.0, 3.0, 4.0};

    public double getContents(int index)
    {
       try
       {
          return numbers[index];
       }
       catch(ArrayIndexOutOfBoundsException e)
       {
          return -1.0;
       }
    }
}

answered May 2, 2016 at 0:00

user2494817

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Comments

Salih Erikci · Accepted Answer · 2016-05-02 00:00:48Z

3

try {
    return numbers[index] ;
}
catch(ArrayIndexOutOfBoundsException exception) {
    return -1;
}

answered May 2, 2016 at 0:00

Salih Erikci

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Comments

Mujtaba Alboori · Accepted Answer · 2016-05-02 00:03:41Z

0

you could do it this way

public double getContents(int index)
 {
  try {
   return numbers[index];
  } catch (ArrayIndexOutOfBoundsException e){
   return -1.0;
  }
 }

otherwise you could just check if the index is larger than the size of your array.

answered May 2, 2016 at 0:03

Mujtaba Alboori

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