Can someone help me to validate the following rules using a RegEx pattern
Max length : 15
Minimum length : 6
Minimum character count : 1
Minimum numbers count : 1
Consequent repeated character count : 2
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1This is probably possible, but will produce very complicated and hard to understand regex (you will have 2 problems: one problem with validating, second with complicated regex). Why not simple function with those checks?Michał Niklas– Michał Niklas2010-09-13 08:06:08 +00:00Commented Sep 13, 2010 at 8:06
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I have already implemented a validation mechanism. But I'm not much comfortable with the RegEx pattern.SLM– SLM2010-09-13 08:11:58 +00:00Commented Sep 13, 2010 at 8:11
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2 Answers
^ # start of string
(?=.{6,15}$) # assert length
(?=.*[A-Za-z]) # assert letter
(?=.*[0-9]) # assert digit
(?:(.)(?!\1\1))* # assert no more than 2 consecutive characters
$ # end of string
will do this. But this won't look nice (or easily maintainable) in JavaScript:
if (/^(?=.{6,15}$)(?=.*[A-Za-z])(?=.*[0-9])(?:(.)(?!\1\1))*$/.test(subject)) {
// Successful match
} else {
// Match attempt failed
}
1 Comment
SLM
Exactly what I have looked for.. Thanks a lot.
I suggest you use a few different regex patterns to check for all those rules cause it will either be impossible or very complicated.
.lengthto check the first 2 rules[a-z](with case insensitive option) for the 3rd rule\dfor the 4th rule(.)\1{2,}for the 5th rule, if this one matches the string contains 3+ character repetitions
2 Comments
Tim Pietzcker
The last one won't catch a password like
a0!!!!. Also, \a-z is invalid, you probably mean [a-z].
Fabian
@Tim, corrected my answer even tho yours has already been accepted