I have the IF statement as follows:
...
if word.endswith('a') or word.endswith('e') or word.endswith('i') or word.endswith('o') or word.endswith('u'):
...
Here I had to use 4 ORs to cover all the circumstances. Is there anyway I can simplify this? I'm using Python 3.4.
Use any
>>> word = 'fa'
>>> any(word.endswith(i) for i in ['a', 'e', 'i', 'o', 'u'])
True
>>> word = 'fe'
>>> any(word.endswith(i) for i in ['a', 'e', 'i', 'o', 'u'])
True
>>>
"aeiou" instead of a list ['a', 'e'] since both list and string are iterables in pythonTry
if word[-1] in ['a','e','i','o','u']:
where word[-1] is the last letter
Simply:
>>> "apple"[-1] in 'aeiou'
True
>>> "boy"[-1] in 'aeiou'
False
word.endswith(c) is just the same as word[-1] == c so:
VOWELS = 'aeiou'
if word[-1] in VOWELS:
print('{} ends with a vowel'.format(word)
will do. There is no need to construct a list, tuple, set, or other data structure: just test membership in a string, in this case VOWELS.
