phpunit mock and php generators

Question

Class: https://github.com/Keanor/generatortest/blob/master/src/SomeClass.php

Test: https://github.com/Keanor/generatortest/blob/master/tests/SomeClassTest.php

Output:

keanor@keanor-pc ~/www/generatortest $ ./vendor/bin/phpunit 
PHPUnit 5.3.2 by Sebastian Bergmann and contributors.

F                                                                   1 / 1 (100%)class Generator#23 (0) {
}


Time: 31 ms, Memory: 3.75Mb

There was 1 failure:

1) AppTest\SomeClassTest::testMethod2
Expectation failed for method name is equal to <string:method1> when invoked 1 time(s).
Method was expected to be called 1 times, actually called 0 times.

FAILURES!
Tests: 1, Assertions: 1, Failures: 1.

if "yield" is replaced by "return" test succeeds!

Mock does not work with a generators?

until you don't iterate the result of the function, this is not really called — Matteo
– Matteo, Commented May 10, 2016 at 11:15

Alexandru Sache · Accepted Answer · 2016-05-11 16:00:02Z

2

It works if you use it like a generator:

    $mock = $this->getMockBuilder(SomeClass::class)
        ->setMethods(['method1'])
        ->getMock();
    $mock->expects($this->once())
        ->method('method1')
        ->willReturn('');
    foreach ($mock->method2() as $result) {
        var_dump($result);
    }

instead of:

    $mock = $this->getMockBuilder(SomeClass::class)
        ->setMethods(['method1'])
        ->getMock();
    $mock->expects($this->once())
        ->method('method1')
        ->willReturn('');
    $result = call_user_func([$mock, 'method2']);
    var_dump($result);

answered May 11, 2016 at 16:00

Alexandru Sache

763 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

phpunit mock and php generators

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related