Appending HTML form value with updates PHP variable

Question

I am wondering if there is a way I can pass an updated PHP counting variable to an HTML form before submission. My PHP reads in a CSV file and generates an HTML table based on the number of rows in the CSV file. The counting variable then reflects the number of rows in the HTML table. Is there anyway I can update the HTML form "request form" with the PHP variable $formvar ?

   <?php
    $csvFile = $_POST['myfile'];
    $formvar =1;
    $row = 0;
    echo "<form id=\"requestform\" action=\"picklist-submit.php\" method=\"post\">";
    echo "<table>";
    echo "<input value=\"Submit\" type=\"submit\">";
    echo "<input type=\"hidden\" name=\"formvar\" value=\"$formvar\">";
    echo "<td>ISBN</td>";
    echo "<td>Quantity</td>";
    echo "<td>Comments</td>";
    echo "<td>Initials</td>";
    echo "</tr>";
if (($handle = fopen($csvFile, "r")) !== FALSE) {
    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
        $num = count($data);
        $row++;
        for ($c=0; $c < $num; $c++) {
          $var = $data[0];
          $var2 = $data[1]; 
          $var3 = $data[2];
          $var4 = $data[3];  
          }
 echo "<tr>";
 echo "<td><input type=\"text\" name=\"upc1\" value=\"$var\"></td>";
 echo "<td><input type=\"text\" name=\"quantity1\" value=\"$var2\"></td>";
 echo "<td><input type=\"text\" name=\"comment1\" value=\"$var3\"></td>";
 echo "<td><input type=\"text\" name=\"initials1\" value=\"$var4\"></td>";
 $formvar++;
    } 
 echo "</tr></table>";
 echo "</form>";
 fclose($handle);
}

?>

dave · Accepted Answer · 2010-09-15 13:26:07Z

3

After echo "</tr></table>";, add:

echo "<input type=\"hidden\" name=\"formvar\" value=\"$formvar\">";

Then when your form is submitted, you can retrieve the value from $_POST['formvar']

answered Sep 15, 2010 at 13:26

dave

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Comments

Mike · Accepted Answer · 2010-09-15 13:32:02Z

0

You can add a field outside of the loop.

    $formvar++;
    } 
echo "<input type=\"hidden\" name=\"formvar\" value=\"".$formvar."\" />"; 
echo "</tr></table>";

You'll also want to remove the hidden field above the loop.

edited Sep 15, 2010 at 13:32

answered Sep 15, 2010 at 13:26

Mike

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