Getting total value of an array with condition

Question

I need to get the total value of this array of all the numbers above or equal to 0. This is the array

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983);

This is the code i have so far, but it only shows the highest number of the array and doesnt count the values up and shows the total.

$totaal = 0;
      for($y=0; $y < count($aReeks); $y++)
      {
          if($totaal < $aReeks[$y] && $aReeks[$y] > 0)
          $totaal = $aReeks[$y];
      }

I have to do it with a for loop.

AbraCadaver · Accepted Answer · 2016-05-13 14:31:38Z

2

Here's a quick way:

$total = array_sum(array_filter($aReeks, function($n) { return $n > 0; }));

Filter the array for values greater than 0
Sum that array

Oh I now see the "I have to do it with a for loop.", so this won't be accepted for your homework I imagine.

answered May 13, 2016 at 14:31

AbraCadaver

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Bikash · Accepted Answer · 2016-05-13 14:17:05Z

1

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 

$total=0;
for($i =0 ; $i< count($aReeks) ; $i++)
{
if($aReeks[$i]>=0)
{
    $total+= $aReeks[$i];
}
}
echo $total ;
?>

Output

11859

answered May 13, 2016 at 14:17

Bikash

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1 Comment

Bikash Over a year ago

If the answer is helpful ,then accept it .So that it may be helpful for others.

Furqan Aziz · Accepted Answer · 2016-05-13 14:18:48Z

0

You are making 2 major mistakes one is in if condition which is $totaal < $aReeks[$y] you don't need this check at all. Secondly rather than summing up the value of each item to the total of all previous items... you are simply assigning the value to the $totaal variable inside the loop.

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 
$totaal = 0;
for($y=0; $y < count($aReeks); $y++)
{
    if($aReeks[$y] > 0)
        $totaal = $totaal + $aReeks[$y];
}

answered May 13, 2016 at 14:18

Furqan Aziz

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