In pseudocode, you can create variables such as 'variable(x)', having x as a forever changing number therefore creating multiple different variables. For example, if:
x = 0
variable(x) = 4
x = 1
variable(x) = 7
then printing 'variable(0)' would give you the result '4' and printing 'variable(1)' would output '7'. My question is: is this possible to do in Python?
You can't use exactly that syntax in Python, but you can come close using a dict.
variable = {}
x = 0
variable[x] = 4
x = 1
variable[x] = 7
print(variable[0])
print(variable[1])
If the domain of your variable is non-negative integers, and you know the largest integer a priori, then you could use a list:
variable = [None]*2
x = 0
variable[x] = 4
x = 1
variable[x] = 7
print(variable[0])
print(variable[1])
The nearest could be a list:
x = []
x.append(4)
x.append(7)
print(x[0])
4
print(x[1])
7
And if you don't want to use a count as identifier you can use Rob's answer.
you can use dictionary
variable = {}
variable['0'] = 4
variable['1'] = 7
x=1
print varibale[x]
will print 7
Seeing as your pseudocode doesn't declare a variable, but a function, it's pretty easy to build something like this:
def my_function(x):
return 3*x + 4
Then you can
print my_function(0)
4
print my_function(1)
7
Of course, you can do pretty much everything in that function; the mathematical linear mapping I used was just an example. You could be reading a whole file, looking for x in it and returning e.g. the line number, you could be tracking satellite positions and return the current position of satellite Nr. x... This is python, a fully-fledged programming language that supports functions, like pretty much every non-declarative programming language I can think of.
def variable(x): return {0:4,1:7}[x]?variable? then you could callvariable[0]to get a valuexto different values??variableas a variable, but as a function ofx.