How to generate a random char array of a specific length using specific characters

Question

I am trying to take this char array here:

char[] options = {'F','Z','P','E','N','T','L','C','D','O'};

and generate a new random char array of a specific length. Like this:

char[] results ={'Z','E','L','C'...} all the way up to a length of 70 characters long. I've already tried to create a new char such as char[] results = new char[70] and then using a for loop to try to get this. But for some reason my mind is blanking. Can anybody refresh me? Thanks all

Might take a look at using this lodash.com/docs#sampleSize Or look at the source if you want to roll your own solution — Legumebo_Magezfeld
– Legumebo_Magezfeld, Commented May 13, 2016 at 22:01
@Legumebo_Magezfeld lodash is for Javascript, his question is about Java. He got the tag wrong. — Barmar
– Barmar, Commented May 13, 2016 at 22:01
Did you try looking at this? stackoverflow.com/questions/2626835/… — vim
– vim, Commented May 13, 2016 at 22:11

zr0gravity7 · Accepted Answer · 2022-04-07 05:06:10Z

4

Kind of straightforward solution

char[] options = {'F','Z','P','E','N','T','L','C','D','O'};
char[] result = new char[70];
Random r=new Random();
for(int i=0;i<result.length;i++){
    result[i]=options[r.nextInt(options.length)];
}

edited Apr 7, 2022 at 5:06

zr0gravity7

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answered May 13, 2016 at 22:13

Antoniossss

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zr0gravity7 · Accepted Answer · 2022-04-07 05:06:42Z

3

private static char[] options = {'F','Z','P','E','N','T','L','C','D','O'};

public static char[] createRandomArray() {
    Random r = new Random();

    char[] arr = new char[70];
    for (int i = 0; i < arr.length; i++) {
        arr[i] = options[r.nextInt(options.length)];
    }
    return  arr;
}

edited Apr 7, 2022 at 5:06

zr0gravity7

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answered May 13, 2016 at 22:14

Alexander Kirakozov

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