Here's a string:
n%3A171717%2Cn%3A%747474%2Cn%3A555666%2Cn%3A1234567&bbn=555666
From this string how can I extract 1234567 ? Need a good logic / syntax.
I guess preg_match would be a better option than explode function in PHP.
It's about a PHP script that extracts data. The numbers can vary and the occurrence of numbers can vary as well only %2Cn%3A will always be there in front of the numbers.the end will always have a &bbn=anyNumber.
That looks like part of an encoded URL so there's bound to be better ways to do it, but urldecoded() your string looks like:
n:171717,n:t7474,n:555666,n:1234567&bbn=555666
So:
preg_match_all('/n:(\d+)/', urldecode($string), $matches);
echo array_pop($matches[1]);
Parenthesized matches are in $matches[1] so just array_pop() to get the last element.
If &bbn= can be anywhere (except for at the beginning) then:
preg_match('/n:(\d+)&bbn=/', urldecode($string), $matches);
echo $matches[1];
&bbn around somewhere else.only %2Cn%3A will always be there in front of the numbers
urldecoded equivalent of %2Cn%3A is ,n:.
The last "enclosing boundary" &bbn remains as is.
preg_match function will do the job:
preg_match("/(?<=,n:)\d+(?=&bbn)/", urldecode("n%3A171717%2Cn%3A%747474%2Cn%3A555666%2Cn%3A1234567&bbn=555666"), $m);
print_r($m[0]); // "1234567"
echo urldecode('n%3A171717%2Cn%3A%747474%2Cn%3A555666%2Cn%3A1234567&bbn=555666');