How to remove part of a string with preg_replace?

Question

Hi I have to remove a part of a string. The code is as follow:-

$string = "19Apr2016";
$search = '_'.$string;

$v1 = "DA6220_19Apr2016";
$v1 = preg_replace("([$search])", "", $v1);
echo $v1 ;

The following code only returns D as output. I want remove _19Apr2016 from the string. Please point out what i am doing wrong.

What part of the string DA6220_19Apr2016 you want to remove ? — Sofiene Djebali
– Sofiene Djebali, Commented May 20, 2016 at 13:56

Murad Hasan · Accepted Answer · 2016-05-20 13:59:38Z

1

Replace,

preg_replace("([$search])", "", $v1);

with,

preg_replace("/$search/", "", $v1);

answered May 20, 2016 at 13:59

Murad Hasan

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Toto · Accepted Answer · 2016-05-25 17:31:21Z

0

[$search] is a character class that means one of character in the list _,1,9,A,p,r,2,0,1,6, when you replace in the string $v1 = "DA6220_19Apr2016" every character that is in the list, you get D, the only character that is not in the list.

You want to use:

$v1 = preg_replace("($search)", "", $v1);

or, using more common regex delimiter:

$v1 = preg_replace("/$search/", "", $v1);

edited May 25, 2016 at 17:31

answered May 20, 2016 at 17:41

Toto

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