0

Is there a way to parse values between a range into a single cell?(preferably delimited?)

For example:

Column A, Cell 1: ID01

Column B, Cell1: ID06

I would like to Column C, Cell 1 output:

ID01;ID02;ID03;ID04;ID05;ID06

I have a similar script that parses the values but adds them per new cell.I'd like to get everything on one cell.

Sub CreateRange()

Dim counter As Integer
Dim cursor As Integer

counter = 2
cursor = 2

While Not IsEmpty(ThisWorkbook.Sheets("Macro2").Range("C" & cursor).Value)
    ThisWorkbook.Sheets("Macro2").Range("A" & counter).Value = ThisWorkbook.Sheets("Macro2").Range("C" & cursor).Value

    While ThisWorkbook.Sheets("Macro2").Range("A" & counter).Value < ThisWorkbook.Sheets("Macro2").Range("D" & cursor).Value
        ThisWorkbook.Sheets("Macro2").Range("A" & counter).Select
        Selection.AutoFill Destination:=ThisWorkbook.Sheets("Macro2").Range("A" & counter & ":" & "A" & counter + 1), Type:=xlFillValues

        counter = counter + 1
        ThisWorkbook.Sheets("Macro2").Range("A" & counter).Select
    Wend
    cursor = cursor + 1
    counter = counter + 1
Wend

ThisWorkbook.Sheets("Macro2").Range("A1").Select

End Sub

Thanks in advance!

3
  • 1
    It can be done. Have you tried anything? In General SO is not a code for me service. Commented May 23, 2016 at 20:48
  • To answer, yes there is. Commented May 23, 2016 at 20:49
  • I have a code that does this but parses each to a new row. I'm trying to get the values on a single row. Commented May 23, 2016 at 20:51

2 Answers 2

1

Try this out:

Sub tryit()
  Dim that As String

  that = ""
  For i = Replace(Range("a1").Value, "ID", "") + 0 To Replace(Range("b1").Value, "ID", "") + 0
    that = that + ";" + "ID" + Format(i, "0#")
  Next

  that = Right(that, Len(that) - 1)

  Range("c1").Value = that
End Sub

Per the question this Takes A1, B1 and iterates over the difference between ID#

Sign up to request clarification or add additional context in comments.

Comments

0

To accomplish this with Excel VBA, use Chip Pearson's String Concatenation function:

http://www.cpearson.com/excel/stringconcatenation.aspx

Copy/paste the below code into a new Module file in your worksheet. Call the function as follows:

=StringConcat(";",A1:B5)

You will get the desired result.

Function StringConcat(Sep As String, ParamArray Args()) As Variant
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' StringConcat
' By Chip Pearson, [email protected], www.cpearson.com
'                  www.cpearson.com/Excel/stringconcatenation.aspx
' This function concatenates all the elements in the Args array,
' delimited by the Sep character, into a single string. This function
' can be used in an array formula. There is a VBA imposed limit that
' a string in a passed in array (e.g.,  calling this function from
' an array formula in a worksheet cell) must be less than 256 characters.
' See the comments at STRING TOO LONG HANDLING for details.
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Dim S As String
Dim N As Long
Dim M As Long
Dim R As Range
Dim NumDims As Long
Dim LB As Long
Dim IsArrayAlloc As Boolean

'''''''''''''''''''''''''''''''''''''''''''
' If no parameters were passed in, return
' vbNullString.
'''''''''''''''''''''''''''''''''''''''''''
If UBound(Args) - LBound(Args) + 1 = 0 Then
    StringConcat = vbNullString
    Exit Function
End If

For N = LBound(Args) To UBound(Args)
    ''''''''''''''''''''''''''''''''''''''''''''''''
    ' Loop through the Args
    ''''''''''''''''''''''''''''''''''''''''''''''''
    If IsObject(Args(N)) = True Then
        '''''''''''''''''''''''''''''''''''''
        ' OBJECT
        ' If we have an object, ensure it
        ' it a Range. The Range object
        ' is the only type of object we'll
        ' work with. Anything else causes
        ' a #VALUE error.
        ''''''''''''''''''''''''''''''''''''
        If TypeOf Args(N) Is Excel.Range Then
            '''''''''''''''''''''''''''''''''''''''''
            ' If it is a Range, loop through the
            ' cells and create append the elements
            ' to the string S.
            '''''''''''''''''''''''''''''''''''''''''
            For Each R In Args(N).Cells
                If Len(R.Text) > 0 Then
                    S = S & R.Text & Sep
                End If
            Next R
        Else
            '''''''''''''''''''''''''''''''''
            ' Unsupported object type. Return
            ' a #VALUE error.
            '''''''''''''''''''''''''''''''''
            StringConcat = CVErr(xlErrValue)
            Exit Function
        End If

    ElseIf IsArray(Args(N)) = True Then
        '''''''''''''''''''''''''''''''''''''
        ' ARRAY
        ' If Args(N) is an array, ensure it
        ' is an allocated array.
        '''''''''''''''''''''''''''''''''''''
        IsArrayAlloc = (Not IsError(LBound(Args(N))) And _
            (LBound(Args(N)) <= UBound(Args(N))))
        If IsArrayAlloc = True Then
            ''''''''''''''''''''''''''''''''''''
            ' The array is allocated. Determine
            ' the number of dimensions of the
            ' array.
            '''''''''''''''''''''''''''''''''''''
            NumDims = 1
            On Error Resume Next
            Err.Clear
            NumDims = 1
            Do Until Err.Number <> 0
                LB = LBound(Args(N), NumDims)
                If Err.Number = 0 Then
                    NumDims = NumDims + 1
                Else
                    NumDims = NumDims - 1
                End If
            Loop
            On Error GoTo 0
            Err.Clear
            ''''''''''''''''''''''''''''''''''
            ' The array must have either
            ' one or two dimensions. Greater
            ' that two caues a #VALUE error.
            ''''''''''''''''''''''''''''''''''
            If NumDims > 2 Then
                StringConcat = CVErr(xlErrValue)
                Exit Function
            End If
            If NumDims = 1 Then
                For M = LBound(Args(N)) To UBound(Args(N))
                    If Args(N)(M) <> vbNullString Then
                        S = S & Args(N)(M) & Sep
                    End If
                Next M

            Else
                ''''''''''''''''''''''''''''''''''''''''''''''''
                ' STRING TOO LONG HANDLING
                ' Here, the error handler must be set to either
                '   On Error GoTo ContinueLoop
                '   or
                '   On Error GoTo ErrH
                ' If you use ErrH, then any error, including
                ' a string too long error, will cause the function
                ' to return #VALUE and quit. If you use ContinueLoop,
                ' the problematic value is ignored and not included
                ' in the result, and the result is the concatenation
                ' of all non-error values in the input. This code is
                ' used in the case that an input string is longer than
                ' 255 characters.
                ''''''''''''''''''''''''''''''''''''''''''''''''
                On Error GoTo ContinueLoop
                'On Error GoTo ErrH
                Err.Clear
                For M = LBound(Args(N), 1) To UBound(Args(N), 1)
                    If Args(N)(M, 1) <> vbNullString Then
                        S = S & Args(N)(M, 1) & Sep
                    End If
                Next M
                Err.Clear
                M = LBound(Args(N), 2)
                If Err.Number = 0 Then
                    For M = LBound(Args(N), 2) To UBound(Args(N), 2)
                        If Args(N)(M, 2) <> vbNullString Then
                            S = S & Args(N)(M, 2) & Sep
                        End If
                    Next M
                End If
                On Error GoTo ErrH:
            End If
        Else
            If Args(N) <> vbNullString Then
                S = S & Args(N) & Sep
            End If
        End If
        Else
        On Error Resume Next
        If Args(N) <> vbNullString Then
            S = S & Args(N) & Sep
        End If
        On Error GoTo 0
    End If
ContinueLoop:
Next N

'''''''''''''''''''''''''''''
' Remove the trailing Sep
'''''''''''''''''''''''''''''
If Len(Sep) > 0 Then
    If Len(S) > 0 Then
        S = Left(S, Len(S) - Len(Sep))
    End If
End If

StringConcat = S
'''''''''''''''''''''''''''''
' Success. Get out.
'''''''''''''''''''''''''''''
Exit Function
ErrH:
'''''''''''''''''''''''''''''
' Error. Return #VALUE
'''''''''''''''''''''''''''''
StringConcat = CVErr(xlErrValue)
End Function

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.