within a dictionary, how do I remove a value from a key with multiple values? Python

Question

from collections import OrderedDict

def main():
    dictionary = OrderedDict()
    dictionary["one"] = ["hello", "blowing"]
    dictionary["two"] = ["frying", "goodbye"]

    for key in dictionary:
        print key, dictionary[key]

    user_input = raw_input("REMOVE BUILDINGS ENDING WITH ING? Y/N")
    if user_input == ("y"):
        print ""
        for key in dictionary:
            for x in dictionary[key]:
                if ("ING") in x or ("ing") in x:
                    del dictionary[key][x]

    print ""

    for key in dictionary:
        print key, dictionary[key]

main()

I am attempting to remove any item with "ing" in it from all keys within a dictionary, example "blowing" from the key "one" and "frying" from the key "two".

The resulting dictionary would go from this:

one ['hello', 'blowing'], two ['frying', 'goodbye']

to this:

one ['hello'], two ['goodbye']

Dmitry Tokarev · Accepted Answer · 2016-05-28 20:04:31Z

1

dict comprehension.

return {x : [i for i in dictionary[x] if not i.lower().endswith('ing')] for x in dictionary}

Edited to replace values ending with 'ing' with 'removed'

return {x : [i if not i.lower().endswith('ing') else 'removed' for i in dictionary[x]] for x in dictionary}

edited May 28, 2016 at 20:04

Dmitry Tokarev

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answered May 28, 2016 at 18:26

TheLazyScripter

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2 Comments

user6240030 Over a year ago

Ok this works nice, can you rework it instead replace that value with "removed"

user6240030 Over a year ago

Awesome! Thank you!

Ani Menon · Accepted Answer · 2016-05-28 18:53:35Z

1

{key: [ele for ele in val if not ele.lower().endswith('ing')] for key, val in d.items()}

Explanation:

Start from the right,

d is the dictionary, it stores <key, [val]>
for each key, val in d we do the following,
[ele for ele in val if not ele.lower().endswith('ing')] means for every element(ele) in list(val) we perform the operations :
- convert each string to lower case
- check if it ends-with `ing'
- then if none of these(if not) then get ele
Then you just print { key: [ele1, ele2, ..] , .. }.

edited May 28, 2016 at 18:53

answered May 28, 2016 at 18:44

Ani Menon

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1 Comment

aldanor Over a year ago

Exact duplicate of my answer ;)

aldanor · Accepted Answer · 2016-05-28 18:20:04Z

0

You can do this in an immutable fashion (i.e., without mutating the original dict) by using a dict comprehension:

>>> d = {'one': ['hello', 'blowing'], 'two': ['frying', 'goodbye']}
>>> {k: [w for w in v if not w.lower().endswith('ing')] for k, v in d.items()}
{'one': ['hello'], 'two': ['goodbye']}

answered May 28, 2016 at 18:20

aldanor

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2 Comments

user6240030 Over a year ago

can you explain what this does?

aldanor Over a year ago

{k: ... for k, v in d.items()} is a dict comprehension, it creates dict with the same keys but altered values. For each key k and value v we iterate over all words w in v, create a new list that contains all such w that their lowered version doesn't end with "ing", and then use this list as a new value in the new dict.

Hackaholic · Accepted Answer · 2016-05-28 18:22:08Z

0

Try this:

>>> collections.OrderedDict({key:filter(lambda x:not x.endswith('ing'), value) for key,value in dictionary.items()})
OrderedDict([('two', ['goodbye']), ('one', ['hello'])])

answered May 28, 2016 at 18:22

Hackaholic

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Comments

Tanu · Accepted Answer · 2016-05-28 18:20:47Z

-1

You were trying to delete with string index not int position reference. Here is the modified code:

from collections import OrderedDict

def main():
    dictionary = OrderedDict()
    dictionary["one"] = ["hello", "blowing"]
    dictionary["two"] = ["frying", "goodbye"]

    for key in dictionary:
        print key, dictionary[key]

    user_input = raw_input("REMOVE BUILDINGS ENDING WITH ING? Y/N")
    if user_input == ("y"):
        print ""
        for key,value in dictionary.iteritems():
            for i,x  in enumerate(value):
                if ("ING") in x or ("ing") in x:
                    del dictionary[key][i]

    print ""

    for key in dictionary:
        print key, dictionary[key]

main()

answered May 28, 2016 at 18:20

Tanu

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2 Comments

user2390182 Over a year ago

This won't work if there are multiple -ing in one list.

Tanu Over a year ago

Oh yes, it wont work fine in that case. User has asked query regarding the shared code , hence it is only meant for tat. so, that he/she can get a understanding of what was wrong.

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