5

I'm using the code below to pick an image file from device gallery:

First I call this piece of code:

Intent i = new Intent();
i.setType("image/*");
i.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(i, "Select Picture"), RESULT_LOAD_IMAGE);

This is my onActivityResult method:

@Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);

        if (requestCode == RESULT_LOAD_IMAGE && resultCode == RESULT_OK && null != data) {

            photoPath  = getPath(data.getData());
            ByteArrayOutputStream baos = new ByteArrayOutputStream();
            FileInputStream fis;
            try {
                fis = new FileInputStream(new File(photoPath));
                byte[] buf = new byte[1024];
                int n;
                while (-1 != (n = fis.read(buf))) {
                    baos.write(buf, 0, n);
                }

                img.setImageBitmap(BitmapFactory.decodeFile(photoPath));

            } catch (Exception e) {
                e.printStackTrace();
            }

        }
    }

And this a helper method to retrieve image path:

private String getPath(Uri uri) {

        String[]  data = { MediaStore.Images.Media.DATA };
        CursorLoader loader = new CursorLoader(getApplicationContext(), uri, data, null, null, null);
        Cursor cursor = loader.loadInBackground();
        int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
        cursor.moveToFirst();
        return cursor.getString(column_index);
    }

My problem is that the app is weird. In my 6.0 emulator, sometimes it works and sometimes No. In an other device (Android 5.1.1) an FileNotFound Exception is thrown at this line

fis = new FileInputStream(new File(photoPath));

All required permissions are fine.Do you guys have any idea what's going on here? Or do you have any better suggestion what to use to pick an image from gallery?

4 Answers 4

7

Try this you can directly set image from onActivityResult

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

        if (requestCode == PICK_IMAGE_REQUEST && resultCode == RESULT_OK && data != null && data.getData() != null) {
try{
            final Uri imageUri = data.getData();
            final InputStream imageStream = getContentResolver().openInputStream(imageUri);
            final Bitmap selectedImage = BitmapFactory.decodeStream(imageStream);

            imageView.setImageBitmap(selectedImage);
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}
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2 Comments

Thank you man, it looks like it's OK. BUT, not working with to large images (aprox. 4MB). It doesn't throw an exception, but either do not display the image. It shows gray image instead, like the image it's too heavy to upload or sth. Anyway to complete this answer, to convert Bitmap to Bytearray this helped me: stackoverflow.com/questions/4989182/….
@user1992 Always Welcome
1

Step #1: Delete the ByteArrayOutputStream, as you are not using it.

Step #2: Delete photoPath = getPath(data.getData()); and the getPath() method, as they are wrong.

Step #3: Use an image loading library to asynchronously populate your ImageView, passing it the Uri (data.getData()) of the image to load. Or, roll lots of your own image-loading code, including forking a background thread and using getContentResolver().openInputStream() to get an InputStream on the content identified by the Uri.

2 Comments

I use ByteArrayOutputStream somewhere else (not shown in the code). So, any solution that might be suggested should take this in count. Thank you!
@user1992: Then roll lots of your own image-loading code, including forking a background thread and using getContentResolver().openInputStream() to get an InputStream on the content identified by the Uri. Use that to populate your ByteArrayOutputStream, and use the byte[] from the ByteArrayOutputStream and BitmapFactory.decodeByteArray() to create your bitmap.
0

you can use like below code

public void pickImage() {
  Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
  intent.setType("image/*");
  startActivityForResult(intent, PICK_PHOTO_FOR_AVATAR);
}

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == PICK_PHOTO_FOR_AVATAR && resultCode == Activity.RESULT_OK) {
        if (data == null) {
            //Display an error
            return;
        }
        InputStream inputStream = context.getContentResolver().openInputStream(data.getData());
        //Now you can do whatever you want with your inpustream, save it as file, upload to a server, decode a bitmap...
    }
}

2 Comments

I don't see any thing different here? Am I missing something?
@user1992: You are missing the fact that this answer uses getContentResolver().openInputStream() to get an InputStream on the content backed by the Uri.
-1

//you are in fragment so use the below code hope its work final Uri imageUri = data.getData();

            final InputStream imageStream =getActivity().getContentResolver().openInputStream(imageUri);

            final Bitmap selectedImage = BitmapFactory.decodeStream(imageStream);

1 Comment

Sorry but: 1. No improvement than existing answers; 2. Text and code not formated; 3. It is not fragment that caused this specific problem. Thanks

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