How to pass multiple parameters in URL to web View in iOS?

Question

I have following dictionary:

NSDictionary *param = @{@"schoolid":@"schooldb1",

                        @"token":del.tokenString,

                        @"mobile":del.phoneString

                        };

NSLog(@"param:%@",param);

I want to send this parameters (schoolid, token, mobile) to web view. But I don't know how to send that. I tried to search on internet but I didn't get any proper solution for my question.

My main URL is:

     NSString *url=@"https://MyURL.com/School/AppSingleTrack";

and I'm going to call UIWebview like following:

NSString *finalurl=[NSString stringWithFormat:@"https://MyURL.com/School/AppSingleTrack/?%@",param];
NSURL *nsurl=[NSURL URLWithString:finalurl];
NSURLRequest *nsrequest=[NSURLRequest requestWithURL:nsurl];
[_webview loadRequest:nsrequest];
[self.view addSubview:_webview];

you would have to i guess inject javascript into webview and call ajax in it with those params. — Shubhank
– Shubhank, Commented Jun 4, 2016 at 7:00
I think you are using NSURLRequest, i am using NSMutableURLRequest, get the response, you need i post the method — Iyyappan Ravi
– Iyyappan Ravi, Commented Jun 4, 2016 at 7:01
thanks for your interest @Shubhank.... but how to do that, can you please post that method in your answer? — TheHungryCub
– TheHungryCub, Commented Jun 4, 2016 at 7:02

Ketan Parmar · Accepted Answer · 2016-06-04 07:01:51Z

1

Try like this,

NSDictionary *param = @{@"schoolid":@"schooldb1",

                        @"token":del.tokenString,

                        @"mobile":del.phoneString

                        };

NSLog(@"param:%@",param);

NSString *url=@"https://24x7tracker.com/School/AppSingleTrack";


NSString *finalurl=[NSString stringWithFormat:@"https://24x7tracker.com/School/AppSingleTrack/"];
NSURL *nsurl=[NSURL URLWithString:finalurl];
NSMutableURLRequest *nsrequest=[NSMutableURLRequest requestWithURL:nsurl];
NSData *data = [NSJSONSerialization dataWithJSONObject:param options:0 error:nil];

[nsrequest setHTTPBody:data];

[_webview loadRequest:nsrequest];
[self.view addSubview:_webview];

set request's necessary properies if require like [nsrequest setHTTPMethod:@"GET"]; or POST and contentType etc.

You should use AFNetworking, It will make it more easier.

answered Jun 4, 2016 at 7:01

Ketan Parmar

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2 Comments

TheHungryCub Over a year ago

@Lion...I tried your solution..there is something wrong. means url with above parameter are not in proper format..... my server side requirement is all that parameter are comma(,) separated.

TheHungryCub Over a year ago

and one another thing... if i add / after AppSingleTrack (as per your code) then it give me 404 error.... after removing that / it give me that another issue(passing data in improper format )

Iyyappan Ravi · Accepted Answer · 2016-06-04 09:02:40Z

0

Use this Code,

    NSString *sUrl =  @"https://24x7tracker.com/School/AppSingleTrack";

    NSMutableURLRequest *res = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:sUrl]];

    [res setHTTPMethod:@"POST"];

    NSDictionary *params; = [NSDictionary dictionaryWithObjectsAndKeys:
                                @"schooldb1",@"schoolid",
                                del.tokenString,@"token",
                                del.phoneString,@"mobile",
                                nil];

    NSMutableArray *pairArray = [[NSMutableArray alloc] initWithCapacity:0];
    for (NSString *key in params)
        [pairArray addObject:[NSString stringWithFormat:@"%@=%@", key, params[key]]];

    [res setHTTPBody:[[pairArray componentsJoinedByString:@"&"] dataUsingEncoding:NSUTF8StringEncoding]];


    [NSURLConnection sendAsynchronousRequest:res
                                   queue:[NSOperationQueue mainQueue]
                       completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {

                           NSLog(@"request URL : %@",res.URL);
                           NSLog(@"request Method : %@",res.HTTPMethod);
                           NSLog(@"parameters : %@",params);
                           NSLog(@"response : %@",response);

                           Resp *r = [ [Resp alloc] initWithDictionary:[NSJSONSerialization JSONObjectWithData: data options: NSJSONReadingMutableContainers error:nil]];

                                   // Success - Show Sucess message
                                    if ([r.sCode isEqualToString:@"success"]) {

                                         NSLog(@"response message : %@",r.sData); 
                                     }

    }];

Use the Class Resp:

Resp.h

#import <Foundation/Foundation.h>

@interface Resp : NSObject

@property (nonatomic, copy) NSString *sCode;
@property (nonatomic, copy) NSString *sMessage;
@property (nonatomic, copy) NSString *sData;


- (id)initWithDictionary:(NSDictionary *)dictionary;

@end

Resp.m

#import "Resp.h"

@implementation Resp

@synthesize sCode             = _id;
@synthesize sMessage          = _title;
@synthesize sData             = _data;


- (id)initWithDictionary:(NSDictionary *)dictionary {

    self = [super init];

    if (self) {
        self.sCode           = [dictionary objectForKey:@"code"];
        self.sMessage        = [dictionary objectForKey:@"message"];
        self.sData           = [dictionary objectForKey:@"data"];
    }

    return self;
}

@end

then finally get the response, hope its helpful

edited Jun 4, 2016 at 9:02

answered Jun 4, 2016 at 7:17

Iyyappan Ravi

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7 Comments

TheHungryCub Over a year ago

I got this error ..."use of undeclared identifier r" ..and this exception- sendAsynchronousRequest i deprecated in ios 9..... @Iyyappan

TheHungryCub Over a year ago

i replace r by res in above code.. then i got following response --: response : <NSHTTPURLResponse: 0x7963fcd0> { URL: 24x7tracker.com/School/html/errorpage.html } { status code: 200, headers { "Accept-Ranges" = bytes; "Cache-Control" = "no-cache, no-store, must-revalidate"; Connection = close; "Content-Length" = 427; "Content-Type" = "text/html"; Date = "Sat, 04 Jun 2016 08:16:46 GMT";Etag = "W/\"427-1459747608000\"";Expires = "Thu, 01 Jan 1970 00:00:00 GMT"; "Last-Modified" = "Mon, 04 Apr 2016 05:26:48 GMT"; Pragma = "no-cache"; Server = Apache;} }

Iyyappan Ravi Over a year ago

I think you got correct response but response data is not get?

TheHungryCub Over a year ago

@Iyyappan.....i get this :(.... 2016-06-04 14:09:29.406 SchoolBusParentApp[926:43894] jsonList: (null)

Iyyappan Ravi Over a year ago

ok i have used class and i update my code, finally run this method

|

Yahoho · Accepted Answer · 2016-06-04 10:15:03Z

0

Firstly, talk to your colleague or check the documents of the URL, to confirm what format of parameters the API needs, and the Request method, such as GET or POST.

Secondly, concatenate the params to the proper format, and don't forget escape the parameters.

If your URL need parameters as normal, try these:

NSDictionary *params = @{@"schoolid" : @"",
                         @"token" : @"",
                         @"mobile" : @""};
NSMutableArray *keyValues = [NSMutableArray array];
for (NSString *key in params) {
    [keyValues addObject:[NSString stringWithFormat:@"%@=%@&", key, params[key]]];
}
NSString *paramsString = [keyValues componentsJoinedByString:@"&"];
paramsString = [paramsString stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLQueryAllowedCharacterSet]];

// Don't add / at last unless the URL has, because / is another path
NSString *baseURL = @"https://24x7tracker.com/School/AppSingleTrack";

// If GET, you can use these two lines, or use below
// NSString *urlString=[NSString stringWithFormat:@"%@?%@", baseURL, paramsString];
// NSURLRequest *request=[NSURLRequest requestWithURL:[NSURL URLWithString:urlString]];


// if POST
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:baseURL]];
request.HTTPMethod = @"POST"; // Default is GET, you can send get request by default,
request.HTTPBody = [paramsString dataUsingEncoding:NSUTF8StringEncoding];

[webView loadRequest:request];

Edit: According to @Shubhank's guess, if the webview's request via ajax, you should confirm the function of javascript, and try these codes in webview's delegate webViewDidFinishLoad:

- (void)webViewDidFinishLoad:(UIWebView *)webView {
    [webView stringByEvaluatingJavaScriptFromString:[NSString stringWithFormat:@"javascriptFunction(%@, %@, %@)", param1, param2, param3]];
}

edited Jun 4, 2016 at 10:15

answered Jun 4, 2016 at 9:58

Yahoho

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2 Comments

TheHungryCub Over a year ago

hey [email protected] side ajax is used....I tried this..but something is wrong

Yahoho Over a year ago

@SurajSukale So, the server side need you pass parameters via invoke the function of javascript, and you know the function name and format of parameters, then invoked the function with stringByEvaluatingJavaScriptFromString in the webViewDidFinishLoad:, but it's still wrong, right? May be you should debug this URL in Chrome or Firefox, and try to directly invoke this function on the console of the Brower.

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