How to format a number with regular expression [duplicate]

Question

I'm having a problem involving formatting a number. Here in Brazil we got a type of document called "CPF", which is a type of personal ID every citizen have.

So here is an example of a correctly formatted CPF number: 096.156.487-09

I'm trying to use a regular expression to format a string containing a CPF number, but I'm having a hard time at it. My current code is returning the unformatted numbers.

For instance: It should output 123.456.789-0 but instead I'm getting 1234567890.

This is my current code:

    String cpf ="09551130401";
    cpf = cpf.replaceAll("(\\d{2})(\\d{3})(\\d{3})(\\d{4})(\\d{2})", "$1.$2.$3-$4");
    System.out.println(cpf);

Seems your regular expression is not matching your input. Your regex wants 14 digits, but gets only 10. — wallenborn
– wallenborn, Commented Jun 7, 2016 at 13:51
Have you tried to count the amount of digits in 09551130401 to see if it matches your regex? Do that and you'll be surprised. — Tom
– Tom, Commented Jun 7, 2016 at 13:51
This is exactly the same question stackoverflow.com/questions/37679323/… asked with another account. — Tunaki
– Tunaki, Commented Jun 7, 2016 at 14:04

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

I'm not sure I get your right .. But maybe you're looking for this pattern:

"(\\d{3})(\\d{3})(\\d{3})(\\d{2})"

And replace with $1.$2.$3-$4.

Online Demo

Full Code:

String cpf ="09551130401";
cpf = cpf.replaceAll("(\\d{3})(\\d{3})(\\d{3})(\\d{2})", "$1.$2.$3-$4");
System.out.println(cpf);
//=> 095.511.304-01

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Jun 7, 2016 at 13:55

Shafizadeh

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