Compare char array element to string literal [duplicate]

Question

I've been trying get part of a string from a char array, and for the life of me, I cannot get any of the examples I've found on StackOverflow to work: Compare string literal vs char array I've looked all over the internet for a solution, I've tried mixing pointers, strcmp, strncmp, everything I can think of.

I cannot see how to get this to work:

#include <stdio.h>

int main(void) {
 const char S[] = "0.9";
 if (S[1] == ".") {
    puts("got it");
 }
 return 0;
}

I realize posting this may ruin my reputation... but I could not find the solution.... similar articles didn't work.

thanks in advance for your help :/

EDIT: I was not aware of the correct search terms to use; that's why I didn't find the specified original.

You are comparing a char value to a char pointer. Change "." to '.'. — barak manos
– barak manos, Commented Jun 7, 2016 at 14:31

MikeCAT · Accepted Answer · 2016-06-07 14:32:08Z

4

"." is a string literal. What you want should be a character constant '.'.

Try this:

#include <stdio.h>
#include <string.h>

int main(void) {
 const char S[] = "0.9";
 if (S[1] == '.') {
    puts("got it");
 }
 return 0;
}

Alternative (but looks worse) way: access an element of the string literal

#include <stdio.h>
#include <string.h>

int main(void) {
 const char S[] = "0.9";
 if (S[1] == "."[0]) {
    puts("got it");
 }
 return 0;
}

answered Jun 7, 2016 at 14:32

MikeCAT

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2 Comments

con Over a year ago

thank you MikeCAT, I learned something new about C today I had never heard this before, an excellent explanation is here: stackoverflow.com/questions/3683602/…

machine_1 Over a year ago

Is it valid to write *"." ??

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