MultiSelect dropdown with checkbox slection using jQuery

Question

I am trying to create a dropdown with multi-select check box manually using jQuery.

I don't want to use any built in libraries other than jQuery. I tried implementing the functionality but the issue is, when I select the check boxes, the data will be popped up in input field, if I click for the second time, I can see that checkboxes are unchecked and data is not appending to previous one.

Please tell me where i went wrong in the code.

<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title>Untitled Document</title>
<style>
    .multiselect {
        width: 200px;
    }
    .selectBox {
        position: relative;
    }
    .selectBox select {
        width: 100%;
        font-weight: bold;
    }
    .overSelect {
        position: absolute;
        left: 0; right: 0; top: 0; bottom: 0;
    }
    #presentationTable {
        display: none;
        border: 1px #dadada solid;
    }
    #presentationTable label {
        display: block;
    }
    #presentationTable label:hover {
        background-color: #1e90ff;
    }
</style>

</head>

<body>
<form>
    <div class="multiselect">
        <div class="selectBox" onClick="showCheckboxes()">
            <input type="text" id="presentatioonTableimputValue"><img src="http://siged.sep.gob.mx/analytics/res/s_blafp/uicomponents/obips.CommonIconSets/dropdownfilled_en_choicelistmulti.png" />
            <div class="overSelect"></div>
        </div>
        <div id="presentationTable"> </div>
    </div>
</form>
<script src="https://code.jquery.com/jquery-2.2.4.min.js"></script>
<script>
    var expanded = false;
    function showCheckboxes()
    {
        var abc = '<label><input type="checkbox" id="one" value="1"/>First1 checkbox</label> <label><input type="checkbox" id="two" value="two"/>Second checkbox </label> <label><input type="checkbox" id="three" value="three"/>Third checkbox</label>';
        $('#presentationTable').html(abc);
                if (!expanded) {
                    $('#presentationTable').show();
                    expanded = true;
                } else {
                    $('#presentationTable').hide();           
                    expanded = false;
                }       
    } 


    function updateTextArea() 
    {
        var allVals = [];
        $('#presentationTable :checked').each(function () {
            allVals.push($(this).val());
        });
        $('#presentatioonTableimputValue').val(allVals);
    }

    $(document).click(function(event){
        var $trigger = $(".multiselect");
        if($trigger !== event.target && !$trigger.has(event.target).length){
            $("#presentationTable").slideUp("fast");

             updateTextArea();
        }           
    });           
</script>
</body>
</html>

I'm confused. "using pure java script. I don't want to use any built in libraries" and there's jquery on it.... — ccasado
– ccasado, Commented Jun 8, 2016 at 7:17

Sabith · Accepted Answer · 2016-06-08 07:33:35Z

4

Try this:

JS

var expanded = false;
populateCheckbox();
function populateCheckbox(){
    var abc = '<label><input type="checkbox" id="one" value="1"/>First1   checkbox</label> <label><input type="checkbox" id="two" value="two"/>Second checkbox </label> <label><input type="checkbox" id="three" value="three"/>Third checkbox</label>';
    $('#presentationTable').html(abc);
}
function showCheckboxes()
 {

            if (!expanded) {
                $('#presentationTable').show();
                expanded = true;
            } else {
                $('#presentationTable').hide();           
                expanded = false;
            }       
} 


function updateTextArea() 
{
        var allVals = [];
        $('#presentationTable :checked').each(function () {
           allVals.push($(this).val());
        });
        $('#presentatioonTableimputValue').val(allVals);

    }
$("#presentationTable label input").click(function(){
    updateTextArea();
});
 $(document).click(function(event){
    var $trigger = $(".multiselect");
    if($trigger !== event.target && !$trigger.has(event.target).length){
        $("#presentationTable").slideUp("fast");

        // updateTextArea();
    }           
});

Each time when you click on the input field, it is creating new checkboxes, That was the issue. hope it will solve your problem.

edited Jun 8, 2016 at 7:33

answered Jun 8, 2016 at 7:18

Sabith

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2 Comments

ccasado Over a year ago

I was about to say the same! Nice and quick catch @sabith

Navyah Over a year ago

@ sabith Thanks for the help, It worked for me . but with small issue, When i click on check box the data is not getting appended to the input text field. when i click on the page then data is getting appended to text box

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