loop of zips in python

Question

I want to create a loop of zips I have sample.csv file with the below entries:

> 1      2       3     4
> a      b       c     d
> apple  banana  cat   dog

and have the below code:

sample= open("sample.csv)
lines = sample.readlines()
testcol = []
for l in lines:
     zipped = zip(testcol ,l)

The output is:

[(('1','a'),'apple'),(('2','b'),'banana'),(('3','c'),'cat'),(('4','d'),'dog')]

but what i want is:

    [('1','a','apple'),('2','b','banana'),('3','c','cat'),('4','d','dog')]

The reason why i have to put it in loops is because my sample.csv may contain arbitrary number of rows.

Kairat · Accepted Answer · 2016-06-14 03:58:34Z

1

This should do the job:

sample = open("sample.csv)
lines = [line.split() for line in sample.readlines()] #splitting on whitespace to create list of lists
zipped = zip(*lines)

See Unpacking Argument Lists:

The reverse situation occurs when the arguments are already in a list or tuple but need to be unpacked for a function call requiring separate positional arguments. For instance, the built-in range() function expects separate start and stop arguments. If they are not available separately, write the function call with the *-operator to unpack the arguments out of a list or tuple.

edited Jun 14, 2016 at 3:58

answered Jun 14, 2016 at 3:48

Kairat

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3 Comments

python novice Over a year ago

thank you for this. zip(*lines) only took the first letter of apple,banana.cat and egg. Also, the reason why i wanted this to e successively zipped is that i may exclude some rows inside the csv file. Thanks.

Kairat Over a year ago

@pythonnovice Check the edit. Each line from csv is split on whitespace so it should work now.

Kairat Over a year ago

@pythonnovice If you want to exclude some rows, you can do something like this: lines = [line.split() for line in sample.readlines() if isGood(line)], where isGood(line) is a method that will return true if the line should be included.

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