Python: functools.partial returns error

Question

I am encountering a problem using functools.partial.

My code:

selected_words = ['awesome', 'great', 'fantastic', 'amazing', 'love', 'horrible', 'bad', 'terrible', 'awful', 'wow', 'hate']

def awsome_count(x,i):
    if selected_words[i] in x:
        y=1
    else:
        y=0
    return y

partialfun=functools.partial(awsome_count,0)

partialfun(products[2]['word_count'])

products is a SFrame.

Error:

TypeError                                 Traceback (most recent call last)
<ipython-input-108-e51348a5d1f0> in <module>()
----> 1 partialfun(products[2]['word_count'])

<ipython-input-66-9ba8c7128add> in awsome_count(x, i)
      1 def awsome_count(x,i):
----> 2     if selected_words[i] in x:
      3         y=1
      4     else:
      5         y=0

TypeError: list indices must be integers, not dict

I am using partial function, is because I want to use apply function:

products['word_count'].apply(functools.partial(awsome_count,0)

Martijn Pieters · Accepted Answer · 2016-06-14 06:59:35Z

4

You gave your partial() object one positional argument:

functools.partial(awsome_count, 0)

That argument is applied first; additional positional arguments are added to that one, so your call:

partialfun(products[2]['word_count'])

becomes:

awesome_count(0, products[2]['word_count'])

which is the wrong order for your function.

If you want to apply a default value for the i argument of your function, use a keyword argument instead of a positional argument:

partialfun = functools.partial(awsome_count, i=0)

Now the call partialfun(products[2]['word_count']) becomes

awsome_count(products[2]['word_count'], i=0)

answered Jun 14, 2016 at 6:59

Martijn Pieters

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2 Comments

alan Over a year ago

Hey, the answer definitely helpful. I voted up just now, not sure whether I incorrectly vote just now. Sorry about that.

Martijn Pieters Over a year ago

No worries, it can't have been you as you can't downvote until you have 125 points or more. :-)

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