Trying to get property of non-object with external json file

Question

This is my JSON file which I get from an external link:

[  
   {  
      "Id":441,
      "Name":"Gary"
   },
   {  
      "Id":1864,
      "Name":"Bob"
   }
]

When I try and display the Id and Name, I receive the error:

Notice: Trying to get property of non-object

$file = file_get_contents('http://linktojson.com');
$decode = json_decode($file, false);
$name = $decode->Name;
$id = $decode->Id;

echo $name;
echo $id;

jszobody · Accepted Answer · 2016-06-17 16:23:47Z

2

Your json data has nested objects. So you need to access it like this:

$decode[0]->Name;

See here: https://3v4l.org/2aY22

Seeing as you have multiple objects with the same structure, you probably want to loop over them, like this:

foreach($decode AS $person) {
    echo $person->Id . ": " . $person->Name;
}

Side note: it really helps to examine your data structure if you're having trouble navigating it. Just doing a var_dump($decode); shows you quite clearly how it is structured and how you need to access it!

edited Jun 17, 2016 at 16:23

answered Jun 17, 2016 at 16:22

jszobody

29k6 gold badges66 silver badges76 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

bob jomes Over a year ago

Ah, that's it! Thanks very much. Also, it only displays the first result. Is it possible to use a foreach loop to display them all?

Collectives™ on Stack Overflow

Trying to get property of non-object with external json file

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related