multiple conditions for JavaScript .includes() method

You can use the .some method referenced here.

The some() method tests whether at least one element in the array passes the test implemented by the provided function.

// test cases
const str1 = 'hi hello, how do you do?';
const str2 = 'regular string';
const str3 = 'hello there';

// do the test strings contain these terms?
const conditions = ["hello", "hi", "howdy"];

// run the tests against every element in the array
const test1 = conditions.some(el => str1.includes(el));
const test2 = conditions.some(el => str2.includes(el));
// strictly check that contains 1 and only one match
const test3 = conditions.reduce((a,c) => a + str3.includes(c), 0) == 1;

// display results
console.log(`Loose matching, 2 matches "${str1}" => ${test1}`);
console.log(`Loose matching, 0 matches "${str2}" => ${test2}`);
console.log(`Exact matching, 1 matches "${str3}" => ${test3}`);

Also, as a user mentions below, it is also interesting to match "exactly one" appearance like mentioned above (and requested by OP). This can be done similarly counting the intersections with .reduce and checking later that they're equal to 1.

With includes(), no, but you can achieve the same thing with REGEX via test():

var value = /hello|hi|howdy/.test(str);

Or, if the words are coming from a dynamic source:

var words = ['hello', 'hi', 'howdy'];
var value = new RegExp(words.join('|')).test(str);

The REGEX approach is a better idea because it allows you to match the words as actual words, not substrings of other words. You just need the word boundary marker \b, so:

var str = 'hilly';
var value = str.includes('hi'); //true, even though the word 'hi' isn't found
var value = /\bhi\b/.test(str); //false - 'hi' appears but not as its own word

You could also do something like this :

const str = "hi, there"

const res = str.includes("hello") || str.includes("hi") || str.includes('howdy');

console.log(res);

Whenever one of your includes return true, value will be true, otherwise, it's going to be false. This works perfectly fine with ES6.

That can be done by using some/every methods of Array and RegEx.

To check whether ALL of words from list(array) are present in the string:

const multiSearchAnd = (text, searchWords) => (
  searchWords.every((el) => {
    return text.match(new RegExp(el,"i"))
  })
)

multiSearchAnd("Chelsey Dietrich Engineer 2018-12-11 Hire", ["cle", "hire"]) //returns false
multiSearchAnd("Chelsey Dietrich Engineer 2018-12-11 Hire", ["che", "hire"]) //returns true

To check whether ANY of words from list(array) are present in the string:

const multiSearchOr = (text, searchWords) => (
  searchWords.some((el) => {
    return text.match(new RegExp(el,"i"))
  })
)

multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["che", "hire"]) //returns true
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["aaa", "hire"]) //returns true
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["che", "zzzz"]) //returns true
multiSearchOr("Chelsey Dietrich Engineer 2018-12-11 Hire", ["aaa", "1111"]) //returns false

Here's a controversial option:

String.prototype.includesOneOf = function(arrayOfStrings) {
  if(!Array.isArray(arrayOfStrings)) {
    throw new Error('includesOneOf only accepts an array')
  }
  return arrayOfStrings.some(str => this.includes(str))
}

Allowing you to do things like:

'Hi, hope you like this option'.toLowerCase().includesOneOf(["hello", "hi", "howdy"]) // True

Not the best answer and not the cleanest, but I think it's more permissive.
Like if you want to use the same filters for all of your checks. Actually .filter() works with an array and returns a filtered array (which I find easier to use too).

var str1 = 'hi, how do you do?';
var str2 = 'regular string';
var conditions = ["hello", "hi", "howdy"];

// Solve the problem
var res1 = [str1].filter(data => data.includes(conditions[0]) || data.includes(conditions[1]) || data.includes(conditions[2]));
var res2 = [str2].filter(data => data.includes(conditions[0]) || data.includes(conditions[1]) || data.includes(conditions[2]));

console.log(res1); // ["hi, how do you do?"]
console.log(res2); // []


// More useful in this case
var text = [str1, str2, "hello world"];

// Apply some filters on data
var res3 = text.filter(data => data.includes(conditions[0]) && data.includes(conditions[2]));
// You may use again the same filters for a different check
var res4 = text.filter(data => data.includes(conditions[0]) || data.includes(conditions[1]));

console.log(res3); // []
console.log(res4); // ["hi, how do you do?", "hello world"]

it depends what context you're using it in. I used it on an object to check if any of the keys had an empty string or null as its value and it worked

Object.values(object).includes('' || null)

Another one!

let result

const givenStr = 'A, X' //values separated by comma or space.

const allowed  = ['A', 'B']
const given    = givenStr.split(/[\s,]+/).filter(v => v)

console.log('given (array):', given)

// given contains none or only allowed values:

result = given.reduce((acc, val) => {
  return acc && allowed.includes(val)
}, true)

console.log('given contains none or only allowed values:', result)

// given contains at least one allowed value:

result = given.reduce((acc, val) => {
  return acc || allowed.includes(val)
}, false)

console.log('given contains at least one allowed value:', result)

Exact matching with array data/

const dataArray = ["amoos", "rifat", "hello"];

const findId = ( data, id ) => {
  let res = data.find(el => el === id )
  return res ? true : false;
}

console.log( findId( dataArray, 'Hi') ) // false
console.log( findId( dataArray, 'amoos') ) // true

Def an old thread but still getting newer replies. I didn't see it on the results and it's one of the easiest ways to use .includes to search for multiple things in a string at once. Depending on what you are trying to do with it just run a for loop that runs through an array of items you want to check a string for using .includes.

Const text = ' does this include item3? ';

For(i = 0; i < arr.length; i++)
{if (text.includes(arr[i])){/* do whatever */ } }

It will return true if any of those items are in that string and then you can have it do whatever.. execute a function, change a variable etc... You can also add what to do if it's false in the if statement as well.

It's worth noting though that it will execute that code for each item that is in the list that returns true so make sure you compensate for that in the code you want executed.

Edit- you could also convert this to a function set it up to pass arguments that are the multiple things you check to see if the string includes and just have it return true or false and you can do whatever with that information outside of the function.

string.match( /apple|banana/ ) // <-- Use Regex

maybe late but here is my solution for an array and two or more items /one|two/.test(['one', 'two', 'three', 'four'].join(' '))

console.log(/one|two/.test(['one', 'two', 'three', 'four'].join(' ')))

Extending String native prototype:

if (!String.prototype.contains) {
    Object.defineProperty(String.prototype, 'contains', {
        value(patterns) {
            if (!Array.isArray(patterns)) {
                return false;
            }

            let value = 0;
            for (let i = 0; i < patterns.length; i++) {
                const pattern = patterns[i];
                value = value + this.includes(pattern);
            }
            return (value === 1);
        }
    });
}

Allowing you to do things like:

console.log('Hi, hope you like this option'.toLowerCase().contains(["hello", "hi", "howdy"])); // True

1 Line solution:

String/Array.prototype.includes('hello' || 'hi' || 'howdy');

let words = 'cucumber, mercy, introduction, shot, howdy'
words.includes('hi' || 'howdy' || 'hello') // true
words.includes('hi' || 'hello') // false