Parsing and creating a dict python

Question

I would like to create a dict by parsing a string

<brns ret = "Herld" other = "very">
<brna name = "ame1">

I would like to create a dict that has the following key-value pairs:

dict = {'brnsret': 'Herld', 
        'brnsother':'very',
        'brnaname':'ame1'}

I have a working script that can handle this:

<brns ret = "Herld">
<brna name = "ame1">

my Code to generate the dict:

match_tag = re.search('<(\w+)\s(\w+) = \"(\w+)\">', each_par_line)
if match_tag is not None:


   dict_tag[match_tag.group(1)+match_tag.group(2)] = match_tag.group(3)

But how should I tweak my script to handle more than one attribute pair in a tag?

Thanks

Why don't you try split the input by space and use list.index() to find '=', get the index (say, a) and generate dict with left and right operand (i.e. in the list, at a-1, a+1) of equals sign? (since I'm not so familiar with regex) — YiFei
– YiFei, Commented Jun 21, 2016 at 1:42

alecxe · Accepted Answer · 2016-06-21 00:20:57Z

2

An alternative option and, probably, just for educational reasons - you can pass this kind of string into a lenient HTML parser like BeautifulSoup:

from bs4 import BeautifulSoup

data = """
<brns ret = "Herld" other = "very">
<brna name = "ame1">
"""

d = {tag.name + attr: value
     for tag in BeautifulSoup(data, "html.parser")()
     for attr, value in tag.attrs.items()}
print(d)

Prints:

{'brnaname': 'ame1', 'brnsother': 'very', 'brnsret': 'Herld'}

answered Jun 21, 2016 at 0:20

alecxe

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