Can anyone offer a clue on how to diagnose the error listed below? Note, I CAN connect to this DB2 instance via DB2 connect, but not thru jdbc.
org.apache.openjpa.persistence.PersistenceException: Unable to open a test
connection to the given database. JDBC url = jdbc:db2://dxxx_xxx.xxx.com:5000/XXXXX:deferPrepares=false, username = NNNNN. Terminating connection pool. Original Exception: ------
com.ibm.db2.jcc.am.SqlSyntaxErrorException: [jcc][10165][10051][3.63.75] Invalid database URL syntax: jdbc:db2:/dxxx_xxx.xxx.com:5000/XXXXX:deferPrepares=false. ERRORCODE=-4461, SQLSTATE=42815
at com.ibm.db2.jcc.am.fd.a(fd.java:679)
at com.ibm.db2.jcc.am.fd.a(fd.java:60)
at com.ibm.db2.jcc.am.fd.a(fd.java:85)
at com.ibm.db2.jcc.DB2Driver.tokenizeURLProperties(DB2Driver.java:911)
at com.ibm.db2.jcc.DB2Driver.connect(DB2Driver.java:408)
at java.sql.DriverManager.getConnection(DriverManager.java:571)
at java.sql.DriverManager.getConnection(DriverManager.java:215)
at com.jolbox.bonecp.BoneCP.obtainRawInternalConnection(BoneCP.java:256)
at com.jolbox.bonecp.BoneCP.<init>(BoneCP.java:305)
at com.jolbox.bonecp.BoneCPDataSource.maybeInit(BoneCPDataSource.java:150)