Creating elements based on values in XSLT

Question

I'm new to XSLT.
I have a source XSLT like the below one.

<?xml version="1.0" encoding="UTF-8"?> 
   <root>
      <child-value>3</child-value>
   </root>

My target should have something like the below one

<?xml version="1.0" encoding="UTF-8"?> 
 <pass_details>
    <pass id ='p1'>1</pass>
    <pass id ='p2'>2</pass>
    <pass id ='p3'>3</pass>
 </pass_details>

The number of <pass> tag should be based on the value of child-value tag? Can any one help with the xslt?

Where is this related to xquery after all? Please restrict to relevant tags. — Jens Erat
– Jens Erat, Commented Jul 3, 2016 at 10:06

michael.hor257k · Accepted Answer · 2016-06-28 21:15:59Z

4

If you're limited to XSLT 1.0, you will have to call a recursive template to generate the pass elements:

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/root">
    <pass_details>
        <xsl:call-template name="gen">
            <xsl:with-param name="n" select="child-value"/>
        </xsl:call-template>
    </pass_details>
</xsl:template>

<xsl:template name="gen">
    <xsl:param name="n"/>
    <xsl:if test="$n > 0">
        <xsl:call-template name="gen">
            <xsl:with-param name="n" select="$n - 1"/>
        </xsl:call-template>
        <pass id="p{$n}">
            <xsl:value-of select="$n"/>
        </pass>
    </xsl:if>   
</xsl:template>

</xsl:stylesheet>

answered Jun 28, 2016 at 21:15

michael.hor257k

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4 Comments

Mohamed Uvais M Over a year ago

Thanks @michael.hor257k. this wrks. One more doubt, Is there any way to convert the date which is string into xsd:date sourceXML : <endDate>2016-07-08T02:05:58.058Z</endDate> targetXML must have <endDate>2016-07-08+05:58</endDate> . In source it is string, where the target expect this as xsd:date. any suggestions.

michael.hor257k Over a year ago

I am sure there is - but please post this as a new question.

Mohamed Uvais M Over a year ago

I have a doubt on the execution of the above xsl. How does the executon happens for the '<xsl:if test="$n > 0"> <xsl:call-template name="gen"> <xsl:with-param name="n" select="$n - 1"/> </xsl:call-template> <pass id="p{$n}"> <xsl:value-of select="$n"/> </pass> </xsl:if> ' whether template will be called first or the pass tag will be executed then the template is called. suggest any tutorial for xslt. thanks

michael.hor257k Over a year ago

The recursive call is executed before outputting the pass element. That is because the counter is counting backwards: 3 , 2, 1, and you want the output in reverse order: 1, 2, 3.

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