Unable to click on href link using selenium

Question

I am unable to open a href link using the code below. I have used the code to store the tag names as web elements and iterated to point to my target href. Please kindly suggest what to change in the above code as the output indicates that there are null references.

String path="http://google.com";

WebDriver driver = new ChromeDriver();
driver.get(path);
driver.manage().window().maximize();

driver.findElement(By.name("q")).sendKeys("hdmi");
driver.findElement(By.name("btnG")).click();


//first get all the <a> elements
List<WebElement> linkList=driver.findElements(By.tagName("a"));

//now traverse over the list and check
for(int i=0 ; i<linkList.size() ; i++)
{
    if(linkList.get(i).getAttribute("href").contains("http://www.hdmi.org/"))
    {
        linkList.get(i).click();
        break;
    }
}

@Andersson the functionality of the code is to open the href link , the code opens google.com and the sends "hdmi" as the keyword. once it opens multiple references to "hdmi" , it will not progress further , where the href link is present. — Anand Ramamurthy
– Anand Ramamurthy, Commented Jul 4, 2016 at 7:04
guys i am new to testing , can i know what is 'chromeDriver' binary; — Anand Ramamurthy
– Anand Ramamurthy, Commented Jul 4, 2016 at 7:17

JeffC · Accepted Answer · 2016-07-05 02:31:47Z

1

You don't have to loop through the links in this case. You can just locate the one you want and click on it. You will have to have a brief wait as the results load or it won't work. I'm guessing that's why your code wasn't working.

driver.findElement(By.name("q")).sendKeys("hdmi");
driver.findElement(By.name("btnG")).click();
WebDriverWait wait = new WebDriverWait(driver, 10);
wait.until(ExpectedConditions.elementToBeClickable(By.cssSelector("a[href*='http://www.hdmi.org/']"))).click();

NOTE: There is more than one link that matches your requirements but this code clicks only the first one.

answered Jul 5, 2016 at 2:31

JeffC

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Saurabh Gaur · Accepted Answer · 2016-07-04 10:53:02Z

1

You need to implement some wait before finding the list as below :-

String path="http://google.com";

WebDriver driver = new ChromeDriver();
driver.get(path);
driver.manage().window().maximize();

driver.findElement(By.name("q")).sendKeys("hdmi");
driver.findElement(By.name("btnG")).click();

//wait..
Thread.sleep(2000);

//first get all the <a> elements
List<WebElement> linkList = driver.findElements(By.tagName("a"));

//now traverse over the list and check
for(WebElement el : linkList)
{
    String link = el.getAttribute("href");
    if((link !=null) && (link.contains("http://www.hdmi.org/")))
    {
        el.click();
        break;
    }
}

For more better solution you can use WebDriverWait here to find that link only without using loop as below :-

driver.findElement(By.name("q")).sendKeys("hdmi");
driver.findElement(By.name("btnG")).click();

WebDriverWait wait = new WebDriverWait(driver, 20);
WebElement link = wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//a[contains(@href,'http://www.hdmi.org/')]")));
link.click();

Hope it will help you...:)

edited Jul 4, 2016 at 10:53

answered Jul 4, 2016 at 10:45

Saurabh Gaur

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1 Comment

JeffC Over a year ago

Using Thread.sleep() in cases like this is not a good practice and isn't necessary.

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